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Two equal positive charges are kept at points A and B. The electric potential at the points between A and B (excluding these points) is studied while moving from A to B. The potential
  • a)
    continuously increases
  • b)
    continuously decreases
  • c)
    increases then decreases
  • d)
    decreases then increases
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Two equal positive charges are kept at points A and B. The electric po...
The potential due to a charge Q is kQ/r, where r is the distance of the point from the charge and k is the constant 1/(4πε).
Let the distance between A and B be dd. So the potential (V) of a point at a distance rr along the line joining A and B is (kq/r)+(kq/(d−r)) , where q is the charge of A and B.

Therefore,
V(r)=kq(1/r+1/(d−r))=kqd/(r.(d−r))

The graph of V with r is - parabola (y=kx²)

Where the potential is along the y axis and the distance r is along the x axis.

So we can see that the potential decreases and then increases on moving from A to B.
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Community Answer
Two equal positive charges are kept at points A and B. The electric po...
Explanation:

  • Electric potential: Electric potential is defined as the amount of work done in bringing a unit positive charge from infinity to a point in the electric field without any acceleration. It is denoted by V.

  • Two equal positive charges: The electric potential at the points between two equal positive charges kept at points A and B (excluding these points) is studied while moving from A to B.

  • Electric potential due to a point charge: The electric potential due to a point charge is given by V=kQ/r, where k is the Coulomb constant, Q is the charge and r is the distance between the point charge and the point where the potential is to be calculated.

  • Electric potential at points between A and B: As we move from point A to point B, the distance from the charge at A decreases and the distance from the charge at B increases. Hence, the electric potential first decreases and then increases.

  • Net electric potential: The net electric potential due to two point charges is the algebraic sum of the electric potentials due to each charge.

  • Equal positive charges: As the charges at A and B are equal and positive, the electric potentials due to both charges are equal in magnitude but opposite in sign. Hence, the net electric potential decreases to a minimum value and then increases.

  • Option D: Therefore, the correct option is D, i.e., the electric potential decreases then increases while moving from A to B.

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Two equal positive charges are kept at points A and B. The electric potential at the points between A and B (excluding these points) is studied while moving from A to B. The potentiala)continuously increasesb)continuously decreasesc)increases then decreasesd)decreases then increasesCorrect answer is option 'D'. Can you explain this answer?
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Two equal positive charges are kept at points A and B. The electric potential at the points between A and B (excluding these points) is studied while moving from A to B. The potentiala)continuously increasesb)continuously decreasesc)increases then decreasesd)decreases then increasesCorrect answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Two equal positive charges are kept at points A and B. The electric potential at the points between A and B (excluding these points) is studied while moving from A to B. The potentiala)continuously increasesb)continuously decreasesc)increases then decreasesd)decreases then increasesCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two equal positive charges are kept at points A and B. The electric potential at the points between A and B (excluding these points) is studied while moving from A to B. The potentiala)continuously increasesb)continuously decreasesc)increases then decreasesd)decreases then increasesCorrect answer is option 'D'. Can you explain this answer?.
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