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In an equilateral triangle of length 6 cm , three masses m1= 40g , m2= 60g and m3= 60g are located at the vertices. The moment of inertia of the system about an axis along the altitude of the triangle passing through mis
  • a)
    1080 g cm2
  • b)
    1020 g cm2
  • c)
    1000 g cm2
  • d)
    1100 g cm2
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
In an equilateral triangle of length 6 cm , three masses m1= 40g , m2=...
Axis is along AD so Moment of inertia of first mass is zero and 2nd and 3rd masses are at distance of 6/2 from axis, so by using simply I=mr2 we get, I=60×36/4+60×36/4=1080 g cm2
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Community Answer
In an equilateral triangle of length 6 cm , three masses m1= 40g , m2=...
M.o. I.is mr^2
so M.o I is 60*6/2*6/2+0+60*6/2*6/2
36*30=1080
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