Two cars leave Delhi at the same time travelling in opposite direction...
Let the speed of first car be x km/hr and second car be y km/hr
therefore, acc. to the question,
If the average speed of the car is 5 km/hr more than that of the other,then
x = y+5...(i)
and
when they are 425km apart at the end of 5 hrs at the end of 5 hrs, then
425 = 5y km + (5y+25)km
425 = 10y+25
425-25=10y
400=10y
or
y =40 km/hr
put in (i), we get,
x = 40+5
x= 45 km/hr
This question is part of UPSC exam. View all Class 8 courses
Two cars leave Delhi at the same time travelling in opposite direction...
Problem Statement:
Two cars leave Delhi at the same time, travelling in opposite directions. The average speed of one car is 5 km per hour more than that of the other. After 5 hours, they are 425 km apart. We need to find the average speed of each car.
Given:
- Two cars leave Delhi at the same time.
- They are travelling in opposite directions.
- The average speed of one car is 5 km per hour more than the other.
- After 5 hours, they are 425 km apart.
Solution:
Let's assume the average speed of one car as x km/hr and the average speed of the other car as (x + 5) km/hr.
Distance covered by the first car:
The distance covered by the first car in 5 hours is 5x km.
Distance covered by the second car:
The distance covered by the second car in 5 hours is 5(x + 5) km.
Since they are travelling in opposite directions, the total distance covered by both cars is equal to the sum of their distances.
Total distance covered:
Total distance covered = Distance covered by the first car + Distance covered by the second car
425 km = 5x + 5(x + 5)
Solving the equation:
425 km = 5x + 5x + 25
425 km = 10x + 25
425 km - 25 = 10x
400 km = 10x
40 km/hr = x
So, the average speed of the first car is 40 km/hr and the average speed of the second car is (40 + 5) km/hr, which is 45 km/hr.
Therefore, the average speed of each car is 40 km/hr and 45 km/hr, respectively.
Two cars leave Delhi at the same time travelling in opposite direction...
Thanks bhaiya
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