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One or More than One Options Correct Type
Direction (Q. Nos. 10-14) This section contains 5 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.
Q.
1-chlorobutane can be reduced to butane by
- a)NaBH4
- b)LiAIH4
- c)Zn/CH3COOH
- d)(C6H5)3SnH
Correct answer is option 'B,C,D'. Can you explain this answer?
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Verified Answer
One or More than One Options Correct TypeDirection (Q. Nos. 10-14) Thi...
1 -chlorobutane is a primary halide, LiAIH4, Zn, (C6 H5)3SnH all reduces it to butane but NaBH4 does not reduce primary halide.
Most Upvoted Answer
One or More than One Options Correct TypeDirection (Q. Nos. 10-14) Thi...
Reduction of 1-chlorobutane to butane
Explanation:
To understand the reduction of 1-chlorobutane to butane, we need to look at the options given and analyze their individual reactions.
a) NaBH4:
NaBH4, also known as sodium borohydride, is a mild reducing agent commonly used in organic chemistry. However, it is not capable of reducing 1-chlorobutane to butane. Therefore, option a) is incorrect.
b) LiAlH4:
LiAlH4, also known as lithium aluminum hydride, is a strong reducing agent that can reduce various functional groups, including halides. It can reduce 1-chlorobutane to butane by breaking the C-Cl bond and substituting it with a hydrogen atom. Therefore, option b) is correct.
c) Zn/CH3COOH:
Zn/CH3COOH is a reagent combination commonly known as zinc and acetic acid. It is not capable of reducing 1-chlorobutane to butane. Therefore, option c) is incorrect.
d) (C6H5)3SnH:
(C6H5)3SnH, also known as triphenyltin hydride, is an organotin compound that can act as a reducing agent. It can reduce 1-chlorobutane to butane by breaking the C-Cl bond and substituting it with a hydrogen atom. Therefore, option d) is correct.
Therefore, the correct options for the reduction of 1-chlorobutane to butane are b) LiAlH4, c) Zn/CH3COOH, and d) (C6H5)3SnH.
Explanation:
To understand the reduction of 1-chlorobutane to butane, we need to look at the options given and analyze their individual reactions.
a) NaBH4:
NaBH4, also known as sodium borohydride, is a mild reducing agent commonly used in organic chemistry. However, it is not capable of reducing 1-chlorobutane to butane. Therefore, option a) is incorrect.
b) LiAlH4:
LiAlH4, also known as lithium aluminum hydride, is a strong reducing agent that can reduce various functional groups, including halides. It can reduce 1-chlorobutane to butane by breaking the C-Cl bond and substituting it with a hydrogen atom. Therefore, option b) is correct.
c) Zn/CH3COOH:
Zn/CH3COOH is a reagent combination commonly known as zinc and acetic acid. It is not capable of reducing 1-chlorobutane to butane. Therefore, option c) is incorrect.
d) (C6H5)3SnH:
(C6H5)3SnH, also known as triphenyltin hydride, is an organotin compound that can act as a reducing agent. It can reduce 1-chlorobutane to butane by breaking the C-Cl bond and substituting it with a hydrogen atom. Therefore, option d) is correct.
Therefore, the correct options for the reduction of 1-chlorobutane to butane are b) LiAlH4, c) Zn/CH3COOH, and d) (C6H5)3SnH.
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One or More than One Options Correct TypeDirection (Q. Nos. 10-14) This section contains 5 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.Q.1-chlorobutane can be reduced to butane bya)NaBH4b)LiAIH4c)Zn/CH3COOHd)(C6H5)3SnHCorrect answer is option 'B,C,D'. Can you explain this answer?
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