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what is the minimum no. of capacitors each of 3uf required to make a circuit with an equivalent capacitance of 2.25 if
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what is the minimum no. of capacitors each of 3uf required to make a c...
The trick to solve these kind of problems is finding the term which has common multiple of 3 and 2.25.As you know 2.25*8=18.then 8/x=1/2.25which means x=18 . This implies there are 8 strips of capacitors in series with capacitance =18.18/3=6 .and each strip has 6 capacitors in parallel.Therefore, total capacitors =8*6=48
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what is the minimum no. of capacitors each of 3uf required to make a c...
**Solution:**
To find the minimum number of capacitors required to achieve an equivalent capacitance of 2.25 µF, we need to consider the concept of capacitors connected in parallel.
**Parallel Connection of Capacitors:**
When capacitors are connected in parallel, the total equivalent capacitance is the sum of individual capacitances. In other words, the total capacitance is obtained by adding the capacitance values of each capacitor.
**Formula for Capacitors in Parallel:**
C_total = C1 + C2 + C3 + ... + Cn
Where C_total is the total equivalent capacitance, and C1, C2, C3, ..., Cn are the individual capacitances.
**Finding the Minimum Number of Capacitors:**
Since the question specifies that the minimum number of capacitors should be used, we need to choose capacitors of the same capacitance value to achieve the desired equivalent capacitance of 2.25 µF.
Let's assume the capacitance of each capacitor to be x µF.
We can now set up an equation using the formula for capacitors in parallel:
2.25 µF = x + x + x + ... + x
Since we want the minimum number of capacitors, we need to distribute the total capacitance evenly among the capacitors.
**Simplifying the Equation:**
Simplifying the equation, we get:
2.25 µF = nx
Dividing both sides of the equation by x:
2.25 µF / x = n
where n represents the number of capacitors required.
**Calculating the Number of Capacitors:**
To find the minimum number of capacitors, we need to find a value for n that is a positive integer. We can start by trying different values of x and checking if the resulting n is an integer.
Let's try x = 0.75 µF:
2.25 µF / 0.75 µF = 3
Since 3 is an integer, we have found a solution. Therefore, the minimum number of capacitors required is 3, with each capacitor having a capacitance of 0.75 µF.
**Conclusion:**
To create a circuit with an equivalent capacitance of 2.25 µF using capacitors of 3 µF, we need a minimum of 3 capacitors, each with a capacitance of 0.75 µF. By connecting these capacitors in parallel, their individual capacitances add up to give the desired equivalent capacitance.
To find the minimum number of capacitors required to achieve an equivalent capacitance of 2.25 µF, we need to consider the concept of capacitors connected in parallel.
**Parallel Connection of Capacitors:**
When capacitors are connected in parallel, the total equivalent capacitance is the sum of individual capacitances. In other words, the total capacitance is obtained by adding the capacitance values of each capacitor.
**Formula for Capacitors in Parallel:**
C_total = C1 + C2 + C3 + ... + Cn
Where C_total is the total equivalent capacitance, and C1, C2, C3, ..., Cn are the individual capacitances.
**Finding the Minimum Number of Capacitors:**
Since the question specifies that the minimum number of capacitors should be used, we need to choose capacitors of the same capacitance value to achieve the desired equivalent capacitance of 2.25 µF.
Let's assume the capacitance of each capacitor to be x µF.
We can now set up an equation using the formula for capacitors in parallel:
2.25 µF = x + x + x + ... + x
Since we want the minimum number of capacitors, we need to distribute the total capacitance evenly among the capacitors.
**Simplifying the Equation:**
Simplifying the equation, we get:
2.25 µF = nx
Dividing both sides of the equation by x:
2.25 µF / x = n
where n represents the number of capacitors required.
**Calculating the Number of Capacitors:**
To find the minimum number of capacitors, we need to find a value for n that is a positive integer. We can start by trying different values of x and checking if the resulting n is an integer.
Let's try x = 0.75 µF:
2.25 µF / 0.75 µF = 3
Since 3 is an integer, we have found a solution. Therefore, the minimum number of capacitors required is 3, with each capacitor having a capacitance of 0.75 µF.
**Conclusion:**
To create a circuit with an equivalent capacitance of 2.25 µF using capacitors of 3 µF, we need a minimum of 3 capacitors, each with a capacitance of 0.75 µF. By connecting these capacitors in parallel, their individual capacitances add up to give the desired equivalent capacitance.
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what is the minimum no. of capacitors each of 3uf required to make a circuit with an equivalent capacitance of 2.25 if
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what is the minimum no. of capacitors each of 3uf required to make a circuit with an equivalent capacitance of 2.25 if for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about what is the minimum no. of capacitors each of 3uf required to make a circuit with an equivalent capacitance of 2.25 if covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for what is the minimum no. of capacitors each of 3uf required to make a circuit with an equivalent capacitance of 2.25 if.
what is the minimum no. of capacitors each of 3uf required to make a circuit with an equivalent capacitance of 2.25 if for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about what is the minimum no. of capacitors each of 3uf required to make a circuit with an equivalent capacitance of 2.25 if covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for what is the minimum no. of capacitors each of 3uf required to make a circuit with an equivalent capacitance of 2.25 if.
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