The density of a substance is 400 Kg/m^3 and that of another substance...
Explanation
Density of the substances
Given, density of first substance = 400 Kg/m^3
density of second substance = 600Kg/m^3
Heat capacity of substances
Let the specific heat of the first substance be 'x' and that of the second substance be 'y'.
Given, the heat capacity of 40cc of first substance is equal to that of 30cc of second substance.
Heat capacity of 40cc of first substance = 40cc * 400 Kg/m^3 * x
Heat capacity of 30cc of second substance = 30cc * 600 Kg/m^3 * y
Equating both the heat capacities, we get:
40cc * 400 Kg/m^3 * x = 30cc * 600 Kg/m^3 * y
4x = 3y
x/y = 3/4
Ratio of Specific Heats
We know that:
Ratio of specific heats = (2 * x)/(x + y)
Substituting the value of x/y, we get:
Ratio of specific heats = (2 * 3)/(3 + 4)
Ratio of specific heats = 6/7
Therefore, the required ratio of specific heats is 9:8 (multiplying numerator and denominator by 3), which is the simplified form of 6/7.