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If |a|=2; |b|=3; |c|=6. angle between a, b and c (vectors) is 120 each then find |a+b+c|?
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If |a|=2; |b|=3; |c|=6. angle between a, b and c (vectors) is 120 each...
Solution:

Step 1: Finding the vector triple product a × b × c

We know that the vector triple product of a, b, and c is given by the formula:

a × b × c = (a · c) b - (a · b) c

where · represents the dot product.

Using this formula, we can find a × b × c as follows:

a × b × c = (a · c) b - (a · b) c

= (2 × 6) b - (2 × 3) c

= 12 b - 6 c

Step 2: Finding the magnitude of a × b × c

To find the magnitude of a × b × c, we can use the formula:

|a × b × c| = |12 b - 6 c|

= |12| |b| |sin(120)| - |6| |c| |sin(120)|

= 6√3 - 9√3

= -3√3

However, since magnitude is always positive, we take the absolute value of -3√3, which gives us:

|a × b × c| = 3√3

Therefore, the magnitude of the vector triple product a × b × c is 3√3.
Community Answer
If |a|=2; |b|=3; |c|=6. angle between a, b and c (vectors) is 120 each...
|a+b+c|2 = |a|2 +|b|2 +|c|2 +2|a||b|.cos120 +2|b||c|.cos120 +2|a||c|.cos 120 =4+9+36-6-18-12 =49-36 =13 ,|a+b+c|=√13
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If |a|=2; |b|=3; |c|=6. angle between a, b and c (vectors) is 120 each then find |a+b+c|?
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If |a|=2; |b|=3; |c|=6. angle between a, b and c (vectors) is 120 each then find |a+b+c|? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If |a|=2; |b|=3; |c|=6. angle between a, b and c (vectors) is 120 each then find |a+b+c|? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If |a|=2; |b|=3; |c|=6. angle between a, b and c (vectors) is 120 each then find |a+b+c|?.
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