Consider following types of bonds.I. Ionic bondII. Covalentσ - bondIII. Coordinate bondIV. Covalentπ - bondQ.All these bonds are present ina)NH4CIb)H2SO4c)NaNO3d)NaN3Correct answer is option 'C'. Can you explain this answer?

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Answer

Option B is correct because firstly u can see there are both ions Na+ and No3- then in No3- there is covalent bond both π nd sigma... nd there is cordinate bonding also... as there can be 2 double bonds and 1 cordinate bond

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Answer

B option is correct

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Answer

The types of bonds present in NaNO3 are:

I. Ionic bond:
- An ionic bond is formed when there is a complete transfer of electrons from one atom to another, resulting in the formation of ions.
- In NaNO3, sodium (Na) is a metal and nitrogen (N) and oxygen (O) are non-metals.
- Sodium loses one electron to become Na+ ion, while nitrogen gains three electrons and oxygen gains two electrons to become N3- and O2- ions, respectively.
- The electrostatic attraction between Na+ and N3- ions, as well as Na+ and O2- ions, forms the ionic bonds in NaNO3.

II. Covalent σ - bond:
- A covalent bond is formed when atoms share electrons to achieve a stable electron configuration.
- In NaNO3, there are covalent σ - bonds between nitrogen and oxygen atoms.
- Nitrogen shares one electron with each of the oxygen atoms, resulting in the formation of nitrogen-oxygen covalent bonds.

III. Coordinate bond:
- A coordinate bond (also known as a dative bond) is formed when one atom donates a pair of electrons to another atom.
- In NaNO3, there are coordinate bonds between the nitrogen atom and one of the oxygen atoms.
- The nitrogen atom donates a lone pair of electrons to the oxygen atom, forming a coordinate bond.

IV. Covalent π - bond:
- A covalent π - bond is formed when there is overlapping of p-orbitals between atoms.
- In NaNO3, there are no covalent π - bonds present.

Conclusion:
- Among the given options, NaNO3 has all the mentioned types of bonds - ionic bond, covalent σ - bond, coordinate bond, and no covalent π - bond.
- Therefore, option 'C' is the correct answer.

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