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If a = 1/ (3-2√2) & b = 1/ ( 3+2√2) then the value of a2 +b2 is :-
- a)34
- b)35
- c)36
- d)37
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If a = 1/ (3-2√2) & b = 1/ ( 3+2√2) then the value of ...
a = 1/ (3-2√2)
b = 1/ ( 3+2√2)
∴ ab = 1/(3-2√2) * 1/ (3+2√2)
=> 1/ (9-8)
=> 1
We know;
(a+b)2 = a2 + b2 + 2ab
And, a2+ b2 = (a+b)2 - 2ab
=> [ 1/(3-2√2) + 1/(3+2√2) ]2 -2*1
=> [3+2√2+3-2√2 / 1]^2 -2
=> (6)2 - 2
=> 36 - 2
=> 34
=> 34
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