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PLEASE ANSWER THIS PHYSICS PROBLEM . A machine gun fires a bullet of mass 40 grams with speed of 1200m/s.The person holding the gun can exert a maximum force of 144N.What is the number of bullets passing from the gun per second?
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Calculating the Number of Bullets Passing from the Gun Per Second:
- Step 1: Calculate the Force Exerted by the Bullet
- The force exerted by the bullet can be calculated using the formula: Force = mass x acceleration.
- The acceleration of the bullet can be calculated using the formula: v^2 = u^2 + 2as, where v is the final velocity (1200 m/s), u is the initial velocity (0 m/s), a is the acceleration, and s is the distance traveled.
- Solving for acceleration gives us a = (v^2)/(2s).
- The force exerted by the bullet is then F_bullet = mass x (v^2)/(2s).
- Step 2: Calculate the Acceleration of the Bullet
- Given that the person holding the gun can exert a maximum force of 144N, the acceleration of the bullet must be less than or equal to 144N/40g.
- Convert the mass of the bullet from grams to kilograms by dividing by 1000: 40g = 0.04kg.
- The maximum acceleration of the bullet is then a_max = 144N / 0.04kg.
- Step 3: Calculate the Distance Traveled by the Bullet
- The distance traveled by the bullet in one second is equal to the muzzle velocity of the bullet (1200 m/s).
- Therefore, the distance traveled by the bullet in one second is s = 1200 m.
- Step 4: Calculate the Number of Bullets Passing from the Gun Per Second
- Substituting the values obtained in Step 2 and Step 3 into the formula for the force exerted by the bullet, we get F_bullet = 0.04kg x (1200^2)/(2 x 1200) = 144N.
- Therefore, the number of bullets passing from the gun per second is 1.
In conclusion, the person holding the gun can fire 1 bullet per second at the maximum force they can exert.
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PLEASE ANSWER THIS PHYSICS PROBLEM . A machine gun fires a bullet of mass 40 grams with speed of 1200m/s.The person holding the gun can exert a maximum force of 144N.What is the number of bullets passing from the gun per second?
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