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Factorize x^3-3x^2-9x-5?
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Factorize x^3-3x^2-9x-5?
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Factorize x^3-3x^2-9x-5?
Factorizing x^3-3x^2-9x-5


Step 1: Identify the Rational Roots

To factorize the given polynomial, we need to find its rational roots using the Rational Root Theorem. The theorem states that if a polynomial has a rational root, then it must be of the form p/q, where p is a factor of the constant term and q is a factor of the leading coefficient.

In this case, the constant term is -5, and the leading coefficient is 1. Therefore, the possible rational roots are:



  • ±1, ±5



Step 2: Test the Rational Roots

We can use synthetic division to test each of the possible rational roots. If a root is indeed a root of the polynomial, then the remainder will be zero.


  • Testing x = 1:




1 | 1 -3 -9 -5
| 1 -2 -11
|___________
1 -2 -11 -16


The remainder is not zero, so x = 1 is not a root of the polynomial.



  • Testing x = -1:




-1 | 1 -3 -9 -5
| -1 4 5
|_________
1 -4 -5 0


The remainder is zero, so x = -1 is a root of the polynomial.


Step 3: Factorize the Polynomial

Now that we know that x = -1 is a root of the polynomial, we can use synthetic division to factorize the polynomial.


-1 | 1 -3 -9 -5
| -1 4 5
|_________
1 -4 -5 0


Using synthetic division, we get:


x^3-3x^2-9x-5 = (x + 1)(x^2 - 4x - 5)


Now we need to factorize the quadratic expression x^2 - 4x - 5. We can use the quadratic formula to find its roots:


x = (-(-4) ± sqrt((-4)^2 - 4(1)(-5))) / (2(1))


x = (4 ± sqrt(36)) / 2


x = 2 ± 3


Therefore, the roots of the quadratic expression are x = 5 and x = -1. We can use these roots to factorize the quadratic expression:


x^2 - 4x - 5 = (x - 5)(x + 1)


Step 4: Final Answer

Substituting the factors of the polynomial, we get:

x^3-3x^2-9x-5 = (
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