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Density of gas = 2.56 g/L temp.= 27 degree Celsius pressure= 1 bar molar mass ?
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Density of gas = 2.56 g/L temp.= 27 degree Celsius pressure= 1 bar mol...
PV = n RT.P V = weight(W) / molecular weight (M) ×R ×T.P M= d R T.as W/V = d ( density ).P = 1 Barr= 10^6 pascals in c.g.s unit.R = 0.0821.T=27 celcius = 27+273=300k.PM= dRT.10^6 M = 2.56 × 0.0821×300.M= 2.56 × 0.0821×300/10^6.M= 256×821×10^-12.M= 210176×10^-12.M= 2.1 ×10^-7.
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Density of gas = 2.56 g/L temp.= 27 degree Celsius pressure= 1 bar molar mass ?
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Density of gas = 2.56 g/L temp.= 27 degree Celsius pressure= 1 bar molar mass ? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Density of gas = 2.56 g/L temp.= 27 degree Celsius pressure= 1 bar molar mass ? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Density of gas = 2.56 g/L temp.= 27 degree Celsius pressure= 1 bar molar mass ?.
Density of gas = 2.56 g/L temp.= 27 degree Celsius pressure= 1 bar molar mass ? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Density of gas = 2.56 g/L temp.= 27 degree Celsius pressure= 1 bar molar mass ? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Density of gas = 2.56 g/L temp.= 27 degree Celsius pressure= 1 bar molar mass ?.
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