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A piece of metal of specific gravity 13.6 is placed in mercury of specific gravity 13.6, what fraction of it volume is under mercury

  • a) 
    the metal piece will simply float over the mercury
  • b) 
    the metal piece will be immersed in mercury by half
  • c) 
    whole of the metal piece will be immersed with its top surface just at mercury level
  • d) 
    metal piece will sink to the bottom
  • e) 
    none of the above
Correct answer is option 'C'. Can you explain this answer?
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A piece of metal of specific gravity 13.6 is placed in mercury of spec...
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Option (c)

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A piece of metal of specific gravity 13.6 is placed in mercury of spec...
Answer:

To determine the fraction of the metal piece's volume that is under the mercury, we need to compare the specific gravities of the metal and the mercury.

The specific gravity of a substance is the ratio of its density to the density of a reference substance, usually water. In this case, both the metal and the mercury have a specific gravity of 13.6, which means they are 13.6 times denser than water.

Understanding Specific Gravity:
- Specific gravity is a measure of the relative density of a substance compared to the density of a reference substance.
- It does not have any units because it is a ratio of two densities.
- The specific gravity of a substance is usually determined by comparing its density to the density of water at a specific temperature.

Effect of Specific Gravity on Buoyancy:
- Buoyancy is the upward force exerted on an object submerged in a fluid.
- It is determined by the difference in density between the object and the fluid.
- If the object is denser than the fluid, it will sink.
- If the object is less dense than the fluid, it will float.
- If the object has the same density as the fluid, it will be in equilibrium and float with its top surface just at the fluid level.

Analysis of the Given Scenario:
- In this scenario, both the metal and the mercury have the same specific gravity of 13.6.
- This means that the metal is equally dense as the mercury.
- As a result, the metal piece will be fully immersed in the mercury with its top surface just at the mercury level.
- This is because the metal piece and the mercury have the same density, causing them to be in equilibrium.

Therefore, the correct answer is option 'C' - the whole of the metal piece will be immersed with its top surface just at the mercury level.
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A piece of metal of specific gravity 13.6 is placed in mercury of specific gravity 13.6, what fraction of it volume is under mercurya)the metal piece will simply float over the mercuryb)the metal piece will be immersed in mercury by halfc)whole of the metal piece will be immersed with its top surface just at mercury leveld)metal piece will sink to the bottome)none of the aboveCorrect answer is option 'C'. Can you explain this answer?
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