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The length of two wires of the same material and diameter are 100cm and 125cm.if same force is applied on them, the elongation in the first wire is 4mm,then the elongation in the second wire (in mm) is ?.the answer for this is 5.Can u explain this ?
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Most Upvoted Answer
The length of two wires of the same material and diameter are 100cm an...
Explanation:

Given, the length of the first wire (L1) = 100cm and the length of the second wire (L2) = 125cm. The force applied on both wires is the same. The elongation in the first wire (e1) is 4mm.

To find the elongation in the second wire (e2), we need to use the formula for the elongation of a wire:

e = (FL) / (A * E * L)

Where F is the force applied, L is the original length of the wire, A is the cross-sectional area of the wire, E is the modulus of elasticity of the material.

Solution:

1. Calculate the cross-sectional area of the wire.
We are given that both wires have the same diameter and material. Therefore, their cross-sectional area is the same. We can use the formula for the area of a circle to find the cross-sectional area.

Area = πr^2
Diameter = 2r
Radius (r) = Diameter / 2

The diameter of the wire is not given in the question. So, we cannot calculate the cross-sectional area.

2. Calculate the modulus of elasticity of the material.
We are not given the modulus of elasticity of the material. So, we cannot calculate the elongation.

Therefore, we cannot find the elongation in the second wire. The answer given in the question is incorrect.
Community Answer
The length of two wires of the same material and diameter are 100cm an...
Y=FL/Al
Y,F ,A , is same for both the wires ...
so equating l/L
4 /100 = l/ 125
l = 5 mm
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Attempt All Questions sub parts from each question.Elasticity vs. plasticity: Objects get deformed when pushed, pulled, and twisted. Elasticity is the measure of the amount that the object can return to its original shape after these external forces and pressure are removed. The opposite of elasticity is plasticity. When something is stretched, and it stays stretched, the material is said to be plastic. Such deformation is said to be plastic deformation. In elastic deformation, atoms of the material are displaced temporarily from their original lattice site. They return back to their original position after the removal of external force. In plastic deformation, atoms of the solid are displaced permanently from their original lattice site. They don’t return back to the original position even after the removal of external load. So, elastic deformation is temporary, whereas plastic deformation is permanent. Amount of elastic deformation is very small. But the amount of plastic deformation is quite large. External force required for elastic deformation of solid is quite small. Force required for plastic deformation is much higher. Total energy absorbed by the material during elastic and plastic deformation region is called modulus of toughness. Energy absorbed by the material during elastic deformation is called module of resilience. Most materials have an amount of force or pressure for which they deform elastically. If more force or pressure is applied, then they undergo plastic deformation. Materials those have a fair amount of plastic deformation before breaking are said to be ductile. Materials those can't stretch or bend much without breaking are said to be brittle. Copper, aluminium etc. are ductile materials. For this reason those are used for making wires. Glass and ceramics are often brittle; they will not bend; they will break.Q. Which of the following statement is false?

Attempt All Questions sub parts from each question.Elasticity vs. plasticity: Objects get deformed when pushed, pulled, and twisted. Elasticity is the measure of the amount that the object can return to its original shape after these external forces and pressure are removed. The opposite of elasticity is plasticity. When something is stretched, and it stays stretched, the material is said to be plastic. Such deformation is said to be plastic deformation. In elastic deformation, atoms of the material are displaced temporarily from their original lattice site. They return back to their original position after the removal of external force. In plastic deformation, atoms of the solid are displaced permanently from their original lattice site. They don’t return back to the original position even after the removal of external load. So, elastic deformation is temporary, whereas plastic deformation is permanent. Amount of elastic deformation is very small. But the amount of plastic deformation is quite large. External force required for elastic deformation of solid is quite small. Force required for plastic deformation is much higher. Total energy absorbed by the material during elastic and plastic deformation region is called modulus of toughness. Energy absorbed by the material during elastic deformation is called module of resilience. Most materials have an amount of force or pressure for which they deform elastically. If more force or pressure is applied, then they undergo plastic deformation. Materials those have a fair amount of plastic deformation before breaking are said to be ductile. Materials those cant stretch or bend much without breaking are said to be brittle. Copper, aluminium etc. are ductile materials. For this reason those are used for making wires. Glass and ceramics are often brittle; they will not bend; they will break.Q. Which of the following 4 stress-strain graphs represent a ductile material and a brittle material?

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The length of two wires of the same material and diameter are 100cm and 125cm.if same force is applied on them, the elongation in the first wire is 4mm,then the elongation in the second wire (in mm) is ?.the answer for this is 5.Can u explain this ?
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The length of two wires of the same material and diameter are 100cm and 125cm.if same force is applied on them, the elongation in the first wire is 4mm,then the elongation in the second wire (in mm) is ?.the answer for this is 5.Can u explain this ? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The length of two wires of the same material and diameter are 100cm and 125cm.if same force is applied on them, the elongation in the first wire is 4mm,then the elongation in the second wire (in mm) is ?.the answer for this is 5.Can u explain this ? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The length of two wires of the same material and diameter are 100cm and 125cm.if same force is applied on them, the elongation in the first wire is 4mm,then the elongation in the second wire (in mm) is ?.the answer for this is 5.Can u explain this ?.
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