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Two insulated charged copper spheres A and B of identical size have charges qa and qb. A third sphere C of the same size but uncharged is brought in contact with first and then with second and finally removed from both. What are the new charges on A and B ?
Verified Answer
Two insulated charged copper spheres A and B of identical size have ch...
A third body which is uncharged contact with body A then both distribute net charge equally .
e.g. Qnet=(0+qa)
because they equally distribute so, both have finally qa/2 charge available.
now third body contact with body B
then Qnet=(qa/2+qb)
now both distribute charge equally
hence,
each has (qa/2+qb)/2
hence finally charge in body A=qa/2
charge in body B=(qa/2+qb)/2=qa/4+qb/2
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Most Upvoted Answer
Two insulated charged copper spheres A and B of identical size have ch...
Initial Situation:
- Sphere A has charge qa and sphere B has charge qb.
- Sphere C is uncharged.
Step 1: Sphere C is brought in contact with sphere A:
- Charges on A and C will redistribute due to contact.
- Final charge on A and C will be (qa + 0)/2 = qa/2.
- Final charge on C will be qa/2.
Step 2: Sphere C is brought in contact with sphere B:
- Charges on B and C will redistribute due to contact.
- Final charge on B and C will be (qb + qa/2)/2 = (2qb + qa)/4 = (qa + qb)/2.
- Final charge on C will be (qa + qb)/2.
Step 3: Sphere C is removed:
- Sphere C is removed after sharing charge with A and B.
- Final charges on A and B will remain (qa + qb)/2.
Conclusion:
- After the process, both spheres A and B will have the same charge of (qa + qb)/2 due to sharing of charges through sphere C.
- Sphere A has charge qa and sphere B has charge qb.
- Sphere C is uncharged.
Step 1: Sphere C is brought in contact with sphere A:
- Charges on A and C will redistribute due to contact.
- Final charge on A and C will be (qa + 0)/2 = qa/2.
- Final charge on C will be qa/2.
Step 2: Sphere C is brought in contact with sphere B:
- Charges on B and C will redistribute due to contact.
- Final charge on B and C will be (qb + qa/2)/2 = (2qb + qa)/4 = (qa + qb)/2.
- Final charge on C will be (qa + qb)/2.
Step 3: Sphere C is removed:
- Sphere C is removed after sharing charge with A and B.
- Final charges on A and B will remain (qa + qb)/2.
Conclusion:
- After the process, both spheres A and B will have the same charge of (qa + qb)/2 due to sharing of charges through sphere C.
Community Answer
Two insulated charged copper spheres A and B of identical size have ch...
Charge on each sphere now is -q1
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Two insulated charged copper spheres A and B of identical size have charges qa and qb. A third sphere C of the same size but uncharged is brought in contact with first and then with second and finally removed from both. What are the new charges on A and B ?
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Two insulated charged copper spheres A and B of identical size have charges qa and qb. A third sphere C of the same size but uncharged is brought in contact with first and then with second and finally removed from both. What are the new charges on A and B ? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Two insulated charged copper spheres A and B of identical size have charges qa and qb. A third sphere C of the same size but uncharged is brought in contact with first and then with second and finally removed from both. What are the new charges on A and B ? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two insulated charged copper spheres A and B of identical size have charges qa and qb. A third sphere C of the same size but uncharged is brought in contact with first and then with second and finally removed from both. What are the new charges on A and B ?.
Two insulated charged copper spheres A and B of identical size have charges qa and qb. A third sphere C of the same size but uncharged is brought in contact with first and then with second and finally removed from both. What are the new charges on A and B ? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Two insulated charged copper spheres A and B of identical size have charges qa and qb. A third sphere C of the same size but uncharged is brought in contact with first and then with second and finally removed from both. What are the new charges on A and B ? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two insulated charged copper spheres A and B of identical size have charges qa and qb. A third sphere C of the same size but uncharged is brought in contact with first and then with second and finally removed from both. What are the new charges on A and B ?.
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