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54 gm of silver reacts with HNO3 to form silver nitrate. Later a displacement reaction takes place when NaCl is added to AgNO3 To form 71.75 gm of AgCl. Find The equivalent mass of the silver. ?
Most Upvoted Answer
54 gm of silver reacts with HNO3 to form silver nitrate. Later a displ...
AgCl = 71.75 gm
[ 54 gm of Ag and (71.75 - 54 ) 17.75 gm of Cl ]...............
Use Following method to solve ::::==>
Equivalent mass
= Mass of metal * 35.5 / Mass of Cl in the chloride .....____
Therefore Equivalent mass = 54 * 35.5 / 17.75 = 54 * 2 = 108....
IS THE ANSWER DEAR.....
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54 gm of silver reacts with HNO3 to form silver nitrate. Later a displacement reaction takes place when NaCl is added to AgNO3 To form 71.75 gm of AgCl. Find The equivalent mass of the silver. ?
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54 gm of silver reacts with HNO3 to form silver nitrate. Later a displacement reaction takes place when NaCl is added to AgNO3 To form 71.75 gm of AgCl. Find The equivalent mass of the silver. ? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about 54 gm of silver reacts with HNO3 to form silver nitrate. Later a displacement reaction takes place when NaCl is added to AgNO3 To form 71.75 gm of AgCl. Find The equivalent mass of the silver. ? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 54 gm of silver reacts with HNO3 to form silver nitrate. Later a displacement reaction takes place when NaCl is added to AgNO3 To form 71.75 gm of AgCl. Find The equivalent mass of the silver. ?.
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