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An isosceles triangle has an area of 8 cm square find the length of its altitude?
Verified Answer
An isosceles triangle has an area of 8 cm square find the length of it...
Both the perpendicular and base are equal in length.
So Area of triangle = 1/2 x b x h 
Let b = h = y
1/2 x y x y = 8
y^2= 16
y = 4
So Perpendicular = Base = 4 cm
Now by Pythagoras theorem,
4^2 + 4^2 = √ 16+ 16 = √32 = 4√2 cm
So required hypotenuse = 4√2 cm
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Most Upvoted Answer
An isosceles triangle has an area of 8 cm square find the length of it...
Let the length of each sides of isosceles triangle be x cm.Then,
Area of triangle = 1/2 base x altitude
Area = 8cm raised to the power 2 (given)
∴ , 8 = 1/2 x raised to the power 2
x raised to the power 2 (square) = 16 = 4
x = 4
length of base and height = 4
now, length of hypotenuse = √ (base)square + (altitude)square
         length of hypotenuse = √ (4)square  + (4)square
         length of hypotenuse = √ 16 + 16
                                           = √32 = 4√2 cm is the solution.
Community Answer
An isosceles triangle has an area of 8 cm square find the length of it...
Isosceles Triangle and its Properties:

An isosceles triangle is a triangle that has two sides of equal length. In an isosceles triangle, the two equal sides are called the legs, and the third side is called the base. The altitude of a triangle is a line segment drawn from a vertex perpendicular to the base or the line containing the base.

Given:
Area of the isosceles triangle = 8 cm²

Finding the Length of the Altitude:
To find the length of the altitude, we need to use the formula for the area of a triangle.

Formula:
Area of a triangle = (1/2) * base * height

Using the Formula:
We are given the area of the isosceles triangle as 8 cm². We can use this information to find the length of the altitude.

Let's assume the base of the isosceles triangle is 'b' and the height (altitude) is 'h'. Since the triangle is isosceles, the two legs are also equal in length.

Calculating the Area:
We know the formula for the area of a triangle, which is (1/2) * base * height. Substituting the given values, we have:

8 = (1/2) * b * h

Simplifying the equation, we get:

16 = b * h

Conclusion:
The length of the altitude (height) of the isosceles triangle is 16 cm.
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An isosceles triangle has an area of 8 cm square find the length of its altitude?
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