What is conc. of C12H22O11 in mol per litre if 20g of it is dissolved ...
Calculation of Concentration of C12H22O11 in a Solution
Given Information:
- Mass of C12H22O11 = 20 g
- Volume of Solution = 2 L
Formula:
Concentration of solute (in mol/L) = Mass of solute (in g) / Molecular weight of solute (in g/mol) / Volume of solution (in L)
Calculation:
- Molecular weight of C12H22O11 = (12 x 12.01) + (22 x 1.01) + (11 x 16.00) = 342.30 g/mol
- Concentration of C12H22O11 = 20 g / 342.30 g/mol / 2 L
- Concentration of C12H22O11 = 0.029 mol/L
Explanation:
The given problem asks us to find the concentration of C12H22O11 in a solution when 20 g of it is dissolved in enough water to make 2 L of solution. The formula for calculating the concentration of a solute in a solution is given as the ratio of mass of solute, molecular weight of solute, and volume of solution.
We first calculate the molecular weight of C12H22O11 and then plug it along with the given mass and volume values into the formula for concentration. After solving, we get the concentration of C12H22O11 in the solution as 0.029 mol/L.
This means that there are 0.029 moles of C12H22O11 present in one liter of the solution. The concentration is an important parameter in chemistry as it helps in determining the properties and behavior of the solution.