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The function 
increases in
increases in- a)(0, 1)
- b)(-∞,e)
- c)(e,∞)
- d)(1, e)
Correct answer is option 'C'. Can you explain this answer?
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The functionincreases ina)(0, 1)b)(-∞,e)c)(e,∞)d)(1...
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The functionincreases ina)(0, 1)b)(-∞,e)c)(e,∞)d)(1...
f'(x) = [(logx).2−2x.1/x](logx)2
= 2(logx−1)/(logx)^2
∴f'(x)>0
⇔logx−1>0
⇔logx>1
⇔logx>loge
⇔x>e
∴f(x) is increasing in (e,∞)
= 2(logx−1)/(logx)^2
∴f'(x)>0
⇔logx−1>0
⇔logx>1
⇔logx>loge
⇔x>e
∴f(x) is increasing in (e,∞)
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The functionincreases ina)(0, 1)b)(-∞,e)c)(e,∞)d)(1, e)Correct answer is option 'C'. Can you explain this answer?
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