Problem: A car starts from rest and accelerates uniformly at 2m/s2 for 10 sec. What is its velocity at the end of 10 sec?

Solution:

To solve this problem, we need to use the kinematic equation:

v = u + at

Where:
v = final velocity
u = initial velocity
a = acceleration
t = time

Given:
u = 0 (since the car starts from rest)
a = 2 m/s2
t = 10 sec

Substituting the given values in the equation, we get:

v = 0 + 2 x 10
v = 20 m/s

Therefore, the velocity of the car at the end of 10 sec is 20 m/s.

Explanation:

The problem involves finding the velocity of a car that starts from rest and accelerates uniformly for 10 seconds. The acceleration of the car is given as 2 m/s2. This means that for every second the car moves, its velocity increases by 2 m/s.

To find the velocity of the car at the end of 10 seconds, we need to use the kinematic equation. The equation relates the final velocity of an object to its initial velocity, acceleration and time.

In this case, the car starts from rest, so its initial velocity is zero. We are given the acceleration, which is 2 m/s2. The time taken by the car to accelerate is 10 seconds.

Substituting these values in the equation, we get the velocity of the car at the end of 10 seconds, which is 20 m/s.

Conclusion:

The velocity of the car at the end of 10 seconds is 20 m/s. This means that the car has increased its speed from 0 m/s to 20 m/s in 10 seconds, with a uniform acceleration of 2 m/s2.

Initial velocity is 0acceleration is 2m/stime is 10secwe have to calculate its final velocitywe can put first equation of motion i. v=u+at=o+2x10=20m/stherefore, final velocity is 20m/s...