Class 9 Exam > Class 9 Questions > A train starts from rest accelerates uniforml...
Start Learning for Free
A train starts from rest accelerates uniformly for 30s to acquire a velocity of 108 km/h.It travels with this velocity for 20 min.The driver then applies the brake and the train retards uniformly to stop after 20s.Find the total distance covered by the train?
Most Upvoted Answer
A train starts from rest accelerates uniformly for 30s to acquire a ve...
Given:
Initial velocity (u) = 0 km/h
Final velocity (v) = 108 km/h
Time taken to accelerate (t1) = 30 s
Time taken to travel at constant velocity (t2) = 20 min = 1200 s
Time taken to decelerate (t3) = 20 s
Calculations:
Step 1: Calculate the acceleration (a) of the train during the first 30 seconds.
Using the formula v = u + at, we can find the acceleration.
v = u + at
108 km/h = 0 km/h + a * 30 s
a = 108 km/h / 30 s = 3.6 km/h/s
Step 2: Calculate the distance (s1) covered during the acceleration period.
Using the formula s = ut + 1/2 at^2, we can find the distance covered during the acceleration period.
s1 = 0 + 1/2 * 3.6 km/h/s * (30 s)^2
s1 = 1620 m
Step 3: Calculate the distance (s2) covered during the constant velocity period.
The distance covered during this period can be calculated using the formula:
s2 = v * t2
s2 = 108 km/h * 1200 s
s2 = 129600 m
Step 4: Calculate the deceleration (b) of the train during the last 20 seconds.
Using the formula v = u + bt, we can find the deceleration.
0 km/h = 108 km/h + b * 20 s
b = -5.4 km/h/s
Note: The negative sign indicates that the train is decelerating.
Step 5: Calculate the distance (s3) covered during the deceleration period.
Using the same formula as in Step 2, we can find the distance covered during the deceleration period.
s3 = 108000 m
Step 6: Calculate the total distance (s) covered by the train.
The total distance can be found by adding up the distances covered during each period.
s = s1 + s2 + s3
s = 1620 m + 129600 m + 108000 m
s = 239220 m
Therefore, the total distance covered by the train is 239220 m.
Initial velocity (u) = 0 km/h
Final velocity (v) = 108 km/h
Time taken to accelerate (t1) = 30 s
Time taken to travel at constant velocity (t2) = 20 min = 1200 s
Time taken to decelerate (t3) = 20 s
Calculations:
Step 1: Calculate the acceleration (a) of the train during the first 30 seconds.
Using the formula v = u + at, we can find the acceleration.
v = u + at
108 km/h = 0 km/h + a * 30 s
a = 108 km/h / 30 s = 3.6 km/h/s
Step 2: Calculate the distance (s1) covered during the acceleration period.
Using the formula s = ut + 1/2 at^2, we can find the distance covered during the acceleration period.
s1 = 0 + 1/2 * 3.6 km/h/s * (30 s)^2
s1 = 1620 m
Step 3: Calculate the distance (s2) covered during the constant velocity period.
The distance covered during this period can be calculated using the formula:
s2 = v * t2
s2 = 108 km/h * 1200 s
s2 = 129600 m
Step 4: Calculate the deceleration (b) of the train during the last 20 seconds.
Using the formula v = u + bt, we can find the deceleration.
0 km/h = 108 km/h + b * 20 s
b = -5.4 km/h/s
Note: The negative sign indicates that the train is decelerating.
Step 5: Calculate the distance (s3) covered during the deceleration period.
Using the same formula as in Step 2, we can find the distance covered during the deceleration period.
s3 = 108000 m
Step 6: Calculate the total distance (s) covered by the train.
The total distance can be found by adding up the distances covered during each period.
s = s1 + s2 + s3
s = 1620 m + 129600 m + 108000 m
s = 239220 m
Therefore, the total distance covered by the train is 239220 m.
Community Answer
A train starts from rest accelerates uniformly for 30s to acquire a ve...
Attention Class 9 Students!
To make sure you are not studying endlessly, EduRev has designed Class 9 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 9.
|
Explore Courses for Class 9 exam
|
|
Similar Class 9 Doubts
Top Courses for Class 9View all
A train starts from rest accelerates uniformly for 30s to acquire a velocity of 108 km/h.It travels with this velocity for 20 min.The driver then applies the brake and the train retards uniformly to stop after 20s.Find the total distance covered by the train?
Question Description
A train starts from rest accelerates uniformly for 30s to acquire a velocity of 108 km/h.It travels with this velocity for 20 min.The driver then applies the brake and the train retards uniformly to stop after 20s.Find the total distance covered by the train? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A train starts from rest accelerates uniformly for 30s to acquire a velocity of 108 km/h.It travels with this velocity for 20 min.The driver then applies the brake and the train retards uniformly to stop after 20s.Find the total distance covered by the train? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A train starts from rest accelerates uniformly for 30s to acquire a velocity of 108 km/h.It travels with this velocity for 20 min.The driver then applies the brake and the train retards uniformly to stop after 20s.Find the total distance covered by the train?.
A train starts from rest accelerates uniformly for 30s to acquire a velocity of 108 km/h.It travels with this velocity for 20 min.The driver then applies the brake and the train retards uniformly to stop after 20s.Find the total distance covered by the train? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A train starts from rest accelerates uniformly for 30s to acquire a velocity of 108 km/h.It travels with this velocity for 20 min.The driver then applies the brake and the train retards uniformly to stop after 20s.Find the total distance covered by the train? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A train starts from rest accelerates uniformly for 30s to acquire a velocity of 108 km/h.It travels with this velocity for 20 min.The driver then applies the brake and the train retards uniformly to stop after 20s.Find the total distance covered by the train?.
Solutions for A train starts from rest accelerates uniformly for 30s to acquire a velocity of 108 km/h.It travels with this velocity for 20 min.The driver then applies the brake and the train retards uniformly to stop after 20s.Find the total distance covered by the train? in English & in Hindi are available as part of our courses for Class 9.
Download more important topics, notes, lectures and mock test series for Class 9 Exam by signing up for free.
Here you can find the meaning of A train starts from rest accelerates uniformly for 30s to acquire a velocity of 108 km/h.It travels with this velocity for 20 min.The driver then applies the brake and the train retards uniformly to stop after 20s.Find the total distance covered by the train? defined & explained in the simplest way possible. Besides giving the explanation of
A train starts from rest accelerates uniformly for 30s to acquire a velocity of 108 km/h.It travels with this velocity for 20 min.The driver then applies the brake and the train retards uniformly to stop after 20s.Find the total distance covered by the train?, a detailed solution for A train starts from rest accelerates uniformly for 30s to acquire a velocity of 108 km/h.It travels with this velocity for 20 min.The driver then applies the brake and the train retards uniformly to stop after 20s.Find the total distance covered by the train? has been provided alongside types of A train starts from rest accelerates uniformly for 30s to acquire a velocity of 108 km/h.It travels with this velocity for 20 min.The driver then applies the brake and the train retards uniformly to stop after 20s.Find the total distance covered by the train? theory, EduRev gives you an
ample number of questions to practice A train starts from rest accelerates uniformly for 30s to acquire a velocity of 108 km/h.It travels with this velocity for 20 min.The driver then applies the brake and the train retards uniformly to stop after 20s.Find the total distance covered by the train? tests, examples and also practice Class 9 tests.
|
|
Explore Courses for Class 9 exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup