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The angle between normal to y square equal to 24 x at (6, 12) and (6 - 12) is?
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The angle between normal to y square equal to 24 x at (6, 12) and (6 -...
Slope of tangent at a point = (dy/dx)
Slope of normal at a point = (-dx/dy)
Angle between normals = angle between their slopes

Angle between slopes = arctan(m1-m2/1+m1m2)

For this curve

dy/dx = 12/y. Therefore -dx/dy= -y/12

Thus m1=1 and m2=-1

Therefore angle is arctan(2/0)=arctan(infinity)
=π/2
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The angle between normal to y square equal to 24 x at (6, 12) and (6 - 12) is?
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