An object is placed 30 centimetre from the reflecting surface in front...
RI n=rea; depth /apparent depth
n=30/x
silvered surface act as a mirror
thus,to get the image 23.2 cm behind,the object should be 23.2 cm i n front
x+thickness of glass=23.2
x+10=23.2
x=23.2-10=13.2
n=30/13.2
=2.272
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An object is placed 30 centimetre from the reflecting surface in front...
Given Information:
- Distance of the object from the reflecting surface (u) = 30 cm
- Thickness of the glass block (t) = 10 cm
- Distance of the image behind the silvered face (v) = 23.2 cm
Calculating Refractive Index:
To calculate the refractive index of the glass, we can use the formula:
Refractive Index (μ) = (Distance of object from the surface (u) + Distance of image behind the surface (v)) / Thickness of the glass (t)
Substituting the given values:
Refractive Index (μ) = (30 cm + 23.2 cm) / 10 cm
Refractive Index (μ) = 53.2 cm / 10 cm
Refractive Index (μ) = 5.32
Explanation:
When light passes through different mediums, it changes its direction due to the change in the refractive index of the medium. In this case, the light passes through air, then the glass block, and finally comes out into the air again after reflecting from the silvered face.
The distance of the object from the reflecting surface is 30 cm, and the distance of the image behind the silvered face is 23.2 cm. To calculate the refractive index of the glass block, we use the formula (u + v) / t, where u is the distance of the object, v is the distance of the image, and t is the thickness of the glass.
By substituting the given values into the formula, we find that the refractive index of the glass block is 5.32.
The refractive index of a material indicates how much the speed of light is reduced when it passes through that material. In this case, the refractive index of 5.32 suggests that the glass block has a relatively high refractive index compared to air. This means that light slows down significantly when it passes through the glass, causing it to bend and form an image behind the silvered face.
The refractive index of a material is an important property that determines how light interacts with it. It is used in various optical calculations and helps in understanding the behavior of light when it passes through different mediums.
An object is placed 30 centimetre from the reflecting surface in front...
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