An object is placed 30 centimetre from the reflecting surface in front of a block of Glass 10 cm thick having its father side silvered. the image is found to be at 23.2 CM behind the silvered face by an observer front of the block . the refractive index of glass is?

Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity

Open App

Class 12 Exam > Class 12 Questions > An object is placed 30 centimetre from the re...

Join the Discussion on the App

An object is placed 30 centimetre from the reflecting surface in front of a block of Glass 10 cm thick having its father side silvered. the image is found to be at 23.2 CM behind the silvered face by an observer front of the block . the refractive index of glass is?

Join for Free

Join for Free

Verified Answer

An object is placed 30 centimetre from the reflecting surface in front...

RI n=rea; depth /apparent depth

n=30/x

silvered surface act as a mirror

thus,to get the image 23.2 cm behind,the object should be 23.2 cm i n front

x+thickness of glass=23.2

x+10=23.2

x=23.2-10=13.2

n=30/13.2

=2.272

This question is part of UPSC exam. View all Class 12 courses

Most Upvoted Answer

An object is placed 30 centimetre from the reflecting surface in front...

Given Information:
- Distance of the object from the reflecting surface (u) = 30 cm
- Thickness of the glass block (t) = 10 cm
- Distance of the image behind the silvered face (v) = 23.2 cm

Calculating Refractive Index:
To calculate the refractive index of the glass, we can use the formula:

Refractive Index (μ) = (Distance of object from the surface (u) + Distance of image behind the surface (v)) / Thickness of the glass (t)

Substituting the given values:
Refractive Index (μ) = (30 cm + 23.2 cm) / 10 cm
Refractive Index (μ) = 53.2 cm / 10 cm
Refractive Index (μ) = 5.32

Explanation:
When light passes through different mediums, it changes its direction due to the change in the refractive index of the medium. In this case, the light passes through air, then the glass block, and finally comes out into the air again after reflecting from the silvered face.

The distance of the object from the reflecting surface is 30 cm, and the distance of the image behind the silvered face is 23.2 cm. To calculate the refractive index of the glass block, we use the formula (u + v) / t, where u is the distance of the object, v is the distance of the image, and t is the thickness of the glass.

By substituting the given values into the formula, we find that the refractive index of the glass block is 5.32.

The refractive index of a material indicates how much the speed of light is reduced when it passes through that material. In this case, the refractive index of 5.32 suggests that the glass block has a relatively high refractive index compared to air. This means that light slows down significantly when it passes through the glass, causing it to bend and form an image behind the silvered face.

The refractive index of a material is an important property that determines how light interacts with it. It is used in various optical calculations and helps in understanding the behavior of light when it passes through different mediums.

Community Answer

An object is placed 30 centimetre from the reflecting surface in front...

200/132

Share via Whatsapp

View all answers Start learning for free

Explore Courses for Class 12 exam

Similar Class 12 Doubts

Read the following text and answer the following questions on the basis of the same:Negative Refractive Index: One of the most fundamental phenomena in optics is refraction. When a beam of light crosses the interface between two different materials, its path is altered depending on the difference in the refractive indices of the materials. The greater the difference, the greater the refraction of the beam. For all known naturally occurring materials the refractive index assumes only positive values. But does this have to be the case?In 1967, Soviet physicist Victor Veselago hypothesized that a material with a negative refractive index could exist without violating any of the laws of physics.Veselago predicted that this remarkable material would exhibit a wide variety of new optical phenomena. However, until recently no one had found such a material and Veselago’s ideas had remained untested. Recently, meta-material samples are being tested for negative refractive index. But the experiments show significant losses and this could be an intrinsic property of negativeindex materials.Snell’s law is satisfied for the materials having a negative refractive index, but the direction of the refracted light ray is ‘mirror-imaged’ about the normal to the surface.There will be an interesting difference in image formation if a vessel is filled with “negative water” having refractive index – 1.33 instead of regular water having refractive index 1.33.Say, there is a fish in a vessel filled with negative water. The position of the fish is such that the observer cannot see it due to normal refraction since the refracted ray does not reach to his eye.But due to negative refraction, he will be able to see it since the refracted ray now reaches his eye.Q. A ray incident on normal glass and “negative glass” at an angle 60°. If the magnitude of angle of refraction in normal glass is 45° then, what will be the magnitude of angle of refraction in the “negative glass”?

View answer

Read the following text and answer the following questions on the basis of the same:Negative Refractive Index: One of the most fundamental phenomena in optics is refraction. When a beam of light crosses the interface between two different materials, its path is altered depending on the difference in the refractive indices of the materials. The greater the difference, the greater the refraction of the beam. For all known naturally occurring materials the refractive index assumes only positive values. But does this have to be the case?In 1967, Soviet physicist Victor Veselago hypothesized that a material with a negative refractive index could exist without violating any of the laws of physics.Veselago predicted that this remarkable material would exhibit a wide variety of new optical phenomena. However, until recently no one had found such a material and Veselago’s ideas had remained untested. Recently, meta-material samples are being tested for negative refractive index. But the experiments show significant losses and this could be an intrinsic property of negativeindex materials.Snell’s law is satisfied for the materials having a negative refractive index, but the direction of the refracted light ray is ‘mirror-imaged’ about the normal to the surface.There will be an interesting difference in image formation if a vessel is filled with “negative water” having refractive index – 1.33 instead of regular water having refractive index 1.33.Say, there is a fish in a vessel filled with negative water. The position of the fish is such that the observer cannot see it due to normal refraction since the refracted ray does not reach to his eye.But due to negative refraction, he will be able to see it since the refracted ray now reaches his eye.Q. When the angle of incidence will be equal to angle of refraction for material having negative refraction index?

View answer

Read the following text and answer the following questions on the basis of the same:Negative Refractive Index: One of the most fundamental phenomena in optics is refraction. When a beam of light crosses the interface between two different materials, its path is altered depending on the difference in the refractive indices of the materials. The greater the difference, the greater the refraction of the beam. For all known naturally occurring materials the refractive index assumes only positive values. But does this have to be the case?In 1967, Soviet physicist Victor Veselago hypothesized that a material with a negative refractive index could exist without violating any of the laws of physics.Veselago predicted that this remarkable material would exhibit a wide variety of new optical phenomena. However, until recently no one had found such a material and Veselago’s ideas had remained untested. Recently, meta-material samples are being tested for negative refractive index. But the experiments show significant losses and this could be an intrinsic property of negativeindex materials.Snell’s law is satisfied for the materials having a negative refractive index, but the direction of the refracted light ray is ‘mirror-imaged’ about the normal to the surface.There will be an interesting difference in image formation if a vessel is filled with “negative water” having refractive index – 1.33 instead of regular water having refractive index 1.33.Say, there is a fish in a vessel filled with negative water. The position of the fish is such that the observer cannot see it due to normal refraction since the refracted ray does not reach to his eye.But due to negative refraction, he will be able to see it since the refracted ray now reaches his eye.Q. Which of the following is the intrinsic property of negative-index materials?

View answer

Read the following text and answer the following questions on the basis of the same:Negative Refractive Index: One of the most fundamental phenomena in optics is refraction. When a beam of light crosses the interface between two different materials, its path is altered depending on the difference in the refractive indices of the materials. The greater the difference, the greater the refraction of the beam. For all known naturally occurring materials the refractive index assumes only positive values. But does this have to be the case?In 1967, Soviet physicist Victor Veselago hypothesized that a material with a negative refractive index could exist without violating any of the laws of physics.Veselago predicted that this remarkable material would exhibit a wide variety of new optical phenomena. However, until recently no one had found such a material and Veselago’s ideas had remained untested. Recently, meta-material samples are being tested for negative refractive index. But the experiments show significant losses and this could be an intrinsic property of negativeindex materials.Snell’s law is satisfied for the materials having a negative refractive index, but the direction of the refracted light ray is ‘mirror-imaged’ about the normal to the surface.There will be an interesting difference in image formation if a vessel is filled with “negative water” having refractive index – 1.33 instead of regular water having refractive index 1.33.Say, there is a fish in a vessel filled with negative water. The position of the fish is such that the observer cannot see it due to normal refraction since the refracted ray does not reach to his eye.But due to negative refraction, he will be able to see it since the refracted ray now reaches his eye.Q. Is Snell’s law applicable for negative refraction ?

View answer

Read the following text and answer the following questions on the basis of the same:Negative Refractive Index: One of the most fundamental phenomena in optics is refraction. When a beam of light crosses the interface between two different materials, its path is altered depending on the difference in the refractive indices of the materials. The greater the difference, the greater the refraction of the beam. For all known naturally occurring materials the refractive index assumes only positive values. But does this have to be the case?In 1967, Soviet physicist Victor Veselago hypothesized that a material with a negative refractive index could exist without violating any of the laws of physics.Veselago predicted that this remarkable material would exhibit a wide variety of new optical phenomena. However, until recently no one had found such a material and Veselago’s ideas had remained untested. Recently, meta-material samples are being tested for negative refractive index. But the experiments show significant losses and this could be an intrinsic property of negativeindex materials.Snell’s law is satisfied for the materials having a negative refractive index, but the direction of the refracted light ray is ‘mirror-imaged’ about the normal to the surface.There will be an interesting difference in image formation if a vessel is filled with “negative water” having refractive index – 1.33 instead of regular water having refractive index 1.33.Say, there is a fish in a vessel filled with negative water. The position of the fish is such that the observer cannot see it due to normal refraction since the refracted ray does not reach to his eye.But due to negative refraction, he will be able to see it since the refracted ray now reaches his eye.Q. Who hypothesized that a material may have a negative refractive index ?

View answer

Share with a Friend

Answer this doubt

Question Description
An object is placed 30 centimetre from the reflecting surface in front of a block of Glass 10 cm thick having its father side silvered. the image is found to be at 23.2 CM behind the silvered face by an observer front of the block . the refractive index of glass is? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An object is placed 30 centimetre from the reflecting surface in front of a block of Glass 10 cm thick having its father side silvered. the image is found to be at 23.2 CM behind the silvered face by an observer front of the block . the refractive index of glass is? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object is placed 30 centimetre from the reflecting surface in front of a block of Glass 10 cm thick having its father side silvered. the image is found to be at 23.2 CM behind the silvered face by an observer front of the block . the refractive index of glass is?.

Solutions for An object is placed 30 centimetre from the reflecting surface in front of a block of Glass 10 cm thick having its father side silvered. the image is found to be at 23.2 CM behind the silvered face by an observer front of the block . the refractive index of glass is? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.

Here you can find the meaning of An object is placed 30 centimetre from the reflecting surface in front of a block of Glass 10 cm thick having its father side silvered. the image is found to be at 23.2 CM behind the silvered face by an observer front of the block . the refractive index of glass is? defined & explained in the simplest way possible. Besides giving the explanation of An object is placed 30 centimetre from the reflecting surface in front of a block of Glass 10 cm thick having its father side silvered. the image is found to be at 23.2 CM behind the silvered face by an observer front of the block . the refractive index of glass is?, a detailed solution for An object is placed 30 centimetre from the reflecting surface in front of a block of Glass 10 cm thick having its father side silvered. the image is found to be at 23.2 CM behind the silvered face by an observer front of the block . the refractive index of glass is? has been provided alongside types of An object is placed 30 centimetre from the reflecting surface in front of a block of Glass 10 cm thick having its father side silvered. the image is found to be at 23.2 CM behind the silvered face by an observer front of the block . the refractive index of glass is? theory, EduRev gives you an ample number of questions to practice An object is placed 30 centimetre from the reflecting surface in front of a block of Glass 10 cm thick having its father side silvered. the image is found to be at 23.2 CM behind the silvered face by an observer front of the block . the refractive index of glass is? tests, examples and also practice Class 12 tests.

Explore Courses for Class 12 exam