Class 12 Exam > Class 12 Questions > Given the data at 25ºC,Ag + I-→ AgI...
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Given the data at 25ºC,
Ag + I- → AgI + e- Eº = 0.152 V
Ag → Ag+ + e- Eº = -0.800 V
What is the value of log Ksp for AgI ?
(2.303 RT/F = 0.059 V) [AIEEE 2006]
- a)+8.612
- b)–37.83
- c)–16.13
- d)–8.12
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Given the data at 25ºC,Ag + I-→ AgI + e- Eº = 0.152 VAg...
The correct answer is option C
AgI (s) + e− ⇌ Ag(s) + I−;
E∘ = −0.152 + Ag(s) → Ag+ + e−
E∘ = −0.8
Agl (s) → Ag+ + I−
E∘ = −0.952
AgI (s) + e− ⇌ Ag(s) + I−;
E∘ = −0.152 + Ag(s) → Ag+ + e−
E∘ = −0.8
Agl (s) → Ag+ + I−
E∘ = −0.952
Most Upvoted Answer
Given the data at 25ºC,Ag + I-→ AgI + e- Eº = 0.152 VAg...
The correct answer is option C
AgI (s) + e− ⇌ Ag(s) + I−;
E∘ = −0.152 + Ag(s) → Ag+ + e−
E∘ = −0.8
Agl (s) → Ag+ + I−
E∘ = −0.952
AgI (s) + e− ⇌ Ag(s) + I−;
E∘ = −0.152 + Ag(s) → Ag+ + e−
E∘ = −0.8
Agl (s) → Ag+ + I−
E∘ = −0.952
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Given the data at 25ºC,Ag + I-→ AgI + e- Eº = 0.152 VAg...
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Given the data at 25ºC,Ag + I-→ AgI + e- Eº = 0.152 VAg →Ag++ e- Eº = -0.800 VWhat is the value of log Kspfor AgI ?(2.303 RT/F = 0.059 V) [AIEEE 2006]a)+8.612b)–37.83c)–16.13d)–8.12Correct answer is option 'C'. Can you explain this answer?
Question Description
Given the data at 25ºC,Ag + I-→ AgI + e- Eº = 0.152 VAg →Ag++ e- Eº = -0.800 VWhat is the value of log Kspfor AgI ?(2.303 RT/F = 0.059 V) [AIEEE 2006]a)+8.612b)–37.83c)–16.13d)–8.12Correct answer is option 'C'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Given the data at 25ºC,Ag + I-→ AgI + e- Eº = 0.152 VAg →Ag++ e- Eº = -0.800 VWhat is the value of log Kspfor AgI ?(2.303 RT/F = 0.059 V) [AIEEE 2006]a)+8.612b)–37.83c)–16.13d)–8.12Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given the data at 25ºC,Ag + I-→ AgI + e- Eº = 0.152 VAg →Ag++ e- Eº = -0.800 VWhat is the value of log Kspfor AgI ?(2.303 RT/F = 0.059 V) [AIEEE 2006]a)+8.612b)–37.83c)–16.13d)–8.12Correct answer is option 'C'. Can you explain this answer?.
Given the data at 25ºC,Ag + I-→ AgI + e- Eº = 0.152 VAg →Ag++ e- Eº = -0.800 VWhat is the value of log Kspfor AgI ?(2.303 RT/F = 0.059 V) [AIEEE 2006]a)+8.612b)–37.83c)–16.13d)–8.12Correct answer is option 'C'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Given the data at 25ºC,Ag + I-→ AgI + e- Eº = 0.152 VAg →Ag++ e- Eº = -0.800 VWhat is the value of log Kspfor AgI ?(2.303 RT/F = 0.059 V) [AIEEE 2006]a)+8.612b)–37.83c)–16.13d)–8.12Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given the data at 25ºC,Ag + I-→ AgI + e- Eº = 0.152 VAg →Ag++ e- Eº = -0.800 VWhat is the value of log Kspfor AgI ?(2.303 RT/F = 0.059 V) [AIEEE 2006]a)+8.612b)–37.83c)–16.13d)–8.12Correct answer is option 'C'. Can you explain this answer?.
Solutions for Given the data at 25ºC,Ag + I-→ AgI + e- Eº = 0.152 VAg →Ag++ e- Eº = -0.800 VWhat is the value of log Kspfor AgI ?(2.303 RT/F = 0.059 V) [AIEEE 2006]a)+8.612b)–37.83c)–16.13d)–8.12Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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ample number of questions to practice Given the data at 25ºC,Ag + I-→ AgI + e- Eº = 0.152 VAg →Ag++ e- Eº = -0.800 VWhat is the value of log Kspfor AgI ?(2.303 RT/F = 0.059 V) [AIEEE 2006]a)+8.612b)–37.83c)–16.13d)–8.12Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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