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A force of 4N acts on a body of mass 2 kg for 4 seconds. Assuming the body to be initially at rest and find the distance covered in 10 seconds after force starts acting on it?
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A force of 4N acts on a body of mass 2 kg for 4 seconds. Assuming the ...
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A force of 4N acts on a body of mass 2 kg for 4 seconds. Assuming the ...
Given information:
- Force (F) = 4N
- Mass (m) = 2 kg
- Time (t) = 4 seconds
Calculating acceleration:
We can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma).
Rearranging the formula, we get:
a = F/m
a = 4N / 2kg
a = 2 m/s²
Calculating initial velocity:
Since the body is initially at rest, the initial velocity (u) is 0 m/s.
Calculating final velocity:
We can use the formula of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is acceleration, and t is time.
v = 0 + (2 m/s²)(4 s)
v = 8 m/s
Calculating distance covered:
To find the distance covered (s), we can use the formula of motion, s = ut + 0.5at².
s = (0 m/s)(10 s) + 0.5(2 m/s²)(10 s)²
s = 0 + 0.5(2 m/s²)(100 s²)
s = 0 + 1 m/s² * 100 s²
s = 100 m
Therefore, the distance covered by the body in 10 seconds after the force starts acting on it is 100 meters.
- Force (F) = 4N
- Mass (m) = 2 kg
- Time (t) = 4 seconds
Calculating acceleration:
We can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma).
Rearranging the formula, we get:
a = F/m
a = 4N / 2kg
a = 2 m/s²
Calculating initial velocity:
Since the body is initially at rest, the initial velocity (u) is 0 m/s.
Calculating final velocity:
We can use the formula of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is acceleration, and t is time.
v = 0 + (2 m/s²)(4 s)
v = 8 m/s
Calculating distance covered:
To find the distance covered (s), we can use the formula of motion, s = ut + 0.5at².
s = (0 m/s)(10 s) + 0.5(2 m/s²)(10 s)²
s = 0 + 0.5(2 m/s²)(100 s²)
s = 0 + 1 m/s² * 100 s²
s = 100 m
Therefore, the distance covered by the body in 10 seconds after the force starts acting on it is 100 meters.
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A force of 4N acts on a body of mass 2 kg for 4 seconds. Assuming the body to be initially at rest and find the distance covered in 10 seconds after force starts acting on it?
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A force of 4N acts on a body of mass 2 kg for 4 seconds. Assuming the body to be initially at rest and find the distance covered in 10 seconds after force starts acting on it? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A force of 4N acts on a body of mass 2 kg for 4 seconds. Assuming the body to be initially at rest and find the distance covered in 10 seconds after force starts acting on it? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A force of 4N acts on a body of mass 2 kg for 4 seconds. Assuming the body to be initially at rest and find the distance covered in 10 seconds after force starts acting on it?.
A force of 4N acts on a body of mass 2 kg for 4 seconds. Assuming the body to be initially at rest and find the distance covered in 10 seconds after force starts acting on it? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A force of 4N acts on a body of mass 2 kg for 4 seconds. Assuming the body to be initially at rest and find the distance covered in 10 seconds after force starts acting on it? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A force of 4N acts on a body of mass 2 kg for 4 seconds. Assuming the body to be initially at rest and find the distance covered in 10 seconds after force starts acting on it?.
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