Question Description
Equation of tangent to a circle x^2 y^2=15,which is perpendicular to the line 4x-y 6=0 is 1.)x 4y-6=0 2.)x 4y √255=0 3.)x 4y-12=0 4.)x 4y 6=0? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Equation of tangent to a circle x^2 y^2=15,which is perpendicular to the line 4x-y 6=0 is 1.)x 4y-6=0 2.)x 4y √255=0 3.)x 4y-12=0 4.)x 4y 6=0? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Equation of tangent to a circle x^2 y^2=15,which is perpendicular to the line 4x-y 6=0 is 1.)x 4y-6=0 2.)x 4y √255=0 3.)x 4y-12=0 4.)x 4y 6=0?.

Solutions for Equation of tangent to a circle x^2 y^2=15,which is perpendicular to the line 4x-y 6=0 is 1.)x 4y-6=0 2.)x 4y √255=0 3.)x 4y-12=0 4.)x 4y 6=0? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Equation of tangent to a circle x^2 y^2=15,which is perpendicular to the line 4x-y 6=0 is 1.)x 4y-6=0 2.)x 4y √255=0 3.)x 4y-12=0 4.)x 4y 6=0? defined & explained in the simplest way possible. Besides giving the explanation of Equation of tangent to a circle x^2 y^2=15,which is perpendicular to the line 4x-y 6=0 is 1.)x 4y-6=0 2.)x 4y √255=0 3.)x 4y-12=0 4.)x 4y 6=0?, a detailed solution for Equation of tangent to a circle x^2 y^2=15,which is perpendicular to the line 4x-y 6=0 is 1.)x 4y-6=0 2.)x 4y √255=0 3.)x 4y-12=0 4.)x 4y 6=0? has been provided alongside types of Equation of tangent to a circle x^2 y^2=15,which is perpendicular to the line 4x-y 6=0 is 1.)x 4y-6=0 2.)x 4y √255=0 3.)x 4y-12=0 4.)x 4y 6=0? theory, EduRev gives you an ample number of questions to practice Equation of tangent to a circle x^2 y^2=15,which is perpendicular to the line 4x-y 6=0 is 1.)x 4y-6=0 2.)x 4y √255=0 3.)x 4y-12=0 4.)x 4y 6=0? tests, examples and also practice JEE tests.