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Find the number of electrons that should be removed from a coin so that it acquires a charge of 10 to the power minus 6 coulomb? answer with solution?
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Calculating the Number of Electrons Removed from a Coin to Acquire a Charge of 10-6 Coulomb

To find the number of electrons that need to be removed from a coin in order for it to acquire a charge of 10-6 Coulomb, we can use the fundamental charge of an electron and the equation Q = ne, where Q is the charge, n is the number of electrons, and e is the elementary charge.

Given:
Charge (Q) = 10-6 C

Solution:

We can rearrange the equation Q = ne to solve for n:
n = Q / e

The elementary charge, e, is equal to 1.6 x 10-19 C.

Substituting the given values into the equation:
n = (10-6 C) / (1.6 x 10-19 C)

To simplify the calculation, we can divide both the numerator and denominator by 10-19:
n = (10-6 C) / (1.6 x 10-19 C) = (1013) / (1.6)

Simplifying further:
n = 6.25 x 1012

Therefore, the number of electrons that need to be removed from the coin is approximately 6.25 x 1012.

Summary:
To acquire a charge of 10-6 Coulomb, approximately 6.25 x 1012 electrons need to be removed from the coin.
Community Answer
Find the number of electrons that should be removed from a coin so tha...
6.25×10^12
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Find the number of electrons that should be removed from a coin so that it acquires a charge of 10 to the power minus 6 coulomb? answer with solution?
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