Given:
The given geometric progression (G.P.) is 5, 25, 125, ...

To Find:
We need to find the 10th term of the G.P. and also determine the nth term of the G.P.

Solution:
We are given the first term (a) as 5, and we need to find the 10th term (T10) of the G.P.

Formula:
The nth term of a G.P. can be found using the formula:
Tn = a * r^(n-1)

Where:
Tn = nth term of the G.P.
a = first term of the G.P.
r = common ratio of the G.P.
n = position of the term in the G.P.

Finding the Common Ratio (r):
To find the common ratio (r) of the G.P., we can divide any term by its previous term.
We can divide the second term (25) by the first term (5):
r = 25/5 = 5

Therefore, the common ratio (r) of the G.P. is 5.

Finding the 10th Term (T10):
Now that we have the first term (a = 5) and the common ratio (r = 5), we can substitute these values into the formula to find the 10th term (T10):
T10 = a * r^(n-1)
T10 = 5 * 5^(10-1)
T10 = 5 * 5^9
T10 = 5 * 1953125
T10 = 9765625

Therefore, the 10th term of the G.P. is 9,765,625.

Finding the nth Term (Tn):
To find the nth term (Tn) of the G.P., we can substitute the given values into the formula:
Tn = a * r^(n-1)

Therefore, the nth term of the G.P. is Tn = a * r^(n-1).

Summary:
- The 10th term of the given G.P. 5, 25, 125, ... is 9,765,625.
- The nth term of the given G.P. 5, 25, 125, ... is Tn = a * r^(n-1).