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Pressure (p) of an ideal gas is related to kinetic energy (E) per unit volume by equation
- a)
- b)
- c)
- d)
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Pressure (p) of an ideal gas is related to kinetic energy (E) per unit...
We know that
K.E = 3/2RT = 3/2pV
Dividing both sides by V
K.E/V = 3/2p
E = 3/2p (here E is K.E per unit volume)
Or p = 2/3E
K.E = 3/2RT = 3/2pV
Dividing both sides by V
K.E/V = 3/2p
E = 3/2p (here E is K.E per unit volume)
Or p = 2/3E
Most Upvoted Answer
Pressure (p) of an ideal gas is related to kinetic energy (E) per unit...
Concept: K.T.GGiven, p is the pressure and E is the K.E. per unit volume.So, we know that K.E = 3/2RT.K.E. =3/2pV.Dividing by volume both side.K.E/V = 3/2pV/V.E = 3/2p.p = 2/3E.Hence, correct answer is (a).
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Pressure (p) of an ideal gas is related to kinetic energy (E) per unit volume by equationa)b)c)d)Correct answer is option 'A'. Can you explain this answer?
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