Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > Find the curl of A = (y cos ax)i + (y + ex)ka... Start Learning for Free
Find the curl of A = (y cos ax)i + (y + ex)k
- a)2i – ex j – cos ax k
- b)i – ex j – cos ax k
- c)2i – ex j + cos ax k
- d)i – ex j + cos ax k
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Find the curl of A = (y cos ax)i + (y + ex)ka)2i – ex j – ...
Answer: b
Explanation: Curl A = i(Dy(y + ex)) – j (Dx(y + ex) – Dz(y cos ax)) + k(-Dy(y cos ax))
= 1.i – j(ex) – k cos ax = i – ex j – cos ax k.
Explanation: Curl A = i(Dy(y + ex)) – j (Dx(y + ex) – Dz(y cos ax)) + k(-Dy(y cos ax))
= 1.i – j(ex) – k cos ax = i – ex j – cos ax k.
Most Upvoted Answer
Find the curl of A = (y cos ax)i + (y + ex)ka)2i – ex j – ...
Free Test
FREE
| Start Free Test |
Community Answer
Find the curl of A = (y cos ax)i + (y + ex)ka)2i – ex j – ...
To find the curl of vector A, we can use the formula for the curl of a vector field:
curl(A) = ∇ x A
Where ∇ is the del operator and x represents the cross product.
Let's calculate the curl step by step.
1. Take the determinant of the following matrix:
| i j k |
| ∂/∂x ∂/∂y ∂/∂z |
| ycos(ax) y eax |
2. Expanding the determinant, we have:
i * (∂/∂y * eax - y * ∂/∂z)
- j * (∂/∂x * eax - ycos(ax) * ∂/∂z)
+ k * (∂/∂x * y - ycos(ax) * ∂/∂y)
3. Taking the partial derivatives:
∂/∂x * y = 0 (constant with respect to x)
∂/∂y * eax = 0 (constant with respect to y)
∂/∂z * eax = 0 (constant with respect to z)
∂/∂x * ycos(ax) = -ay * sin(ax)
∂/∂y * ycos(ax) = cos(ax) - ay * x * sin(ax)
∂/∂z * ycos(ax) = 0 (constant with respect to z)
4. Simplifying the expression:
i * (- y * ∂/∂z) = -y * (∂/∂z)
- j * (∂/∂x * eax) = -(0)
+ k * (cos(ax) - ay * x * sin(ax)) = cos(ax) - ay * x * sin(ax)
5. Combining the terms:
curl(A) = -y * (∂/∂z)i + (cos(ax) - ay * x * sin(ax))k
Therefore, the curl of vector A is -y * (∂/∂z)i + (cos(ax) - ay * x * sin(ax))k.
curl(A) = ∇ x A
Where ∇ is the del operator and x represents the cross product.
Let's calculate the curl step by step.
1. Take the determinant of the following matrix:
| i j k |
| ∂/∂x ∂/∂y ∂/∂z |
| ycos(ax) y eax |
2. Expanding the determinant, we have:
i * (∂/∂y * eax - y * ∂/∂z)
- j * (∂/∂x * eax - ycos(ax) * ∂/∂z)
+ k * (∂/∂x * y - ycos(ax) * ∂/∂y)
3. Taking the partial derivatives:
∂/∂x * y = 0 (constant with respect to x)
∂/∂y * eax = 0 (constant with respect to y)
∂/∂z * eax = 0 (constant with respect to z)
∂/∂x * ycos(ax) = -ay * sin(ax)
∂/∂y * ycos(ax) = cos(ax) - ay * x * sin(ax)
∂/∂z * ycos(ax) = 0 (constant with respect to z)
4. Simplifying the expression:
i * (- y * ∂/∂z) = -y * (∂/∂z)
- j * (∂/∂x * eax) = -(0)
+ k * (cos(ax) - ay * x * sin(ax)) = cos(ax) - ay * x * sin(ax)
5. Combining the terms:
curl(A) = -y * (∂/∂z)i + (cos(ax) - ay * x * sin(ax))k
Therefore, the curl of vector A is -y * (∂/∂z)i + (cos(ax) - ay * x * sin(ax))k.
 | Explore Courses for Electrical Engineering (EE) exam |  |
Top Courses for Electrical Engineering (EE)View all
Top Courses for Electrical Engineering (EE)
Question Description
Find the curl of A = (y cos ax)i + (y + ex)ka)2i – ex j – cos ax kb)i – ex j – cos ax kc)2i – ex j + cos ax kd)i – ex j + cos ax kCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Find the curl of A = (y cos ax)i + (y + ex)ka)2i – ex j – cos ax kb)i – ex j – cos ax kc)2i – ex j + cos ax kd)i – ex j + cos ax kCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the curl of A = (y cos ax)i + (y + ex)ka)2i – ex j – cos ax kb)i – ex j – cos ax kc)2i – ex j + cos ax kd)i – ex j + cos ax kCorrect answer is option 'B'. Can you explain this answer?.
Find the curl of A = (y cos ax)i + (y + ex)ka)2i – ex j – cos ax kb)i – ex j – cos ax kc)2i – ex j + cos ax kd)i – ex j + cos ax kCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Find the curl of A = (y cos ax)i + (y + ex)ka)2i – ex j – cos ax kb)i – ex j – cos ax kc)2i – ex j + cos ax kd)i – ex j + cos ax kCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the curl of A = (y cos ax)i + (y + ex)ka)2i – ex j – cos ax kb)i – ex j – cos ax kc)2i – ex j + cos ax kd)i – ex j + cos ax kCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Find the curl of A = (y cos ax)i + (y + ex)ka)2i – ex j – cos ax kb)i – ex j – cos ax kc)2i – ex j + cos ax kd)i – ex j + cos ax kCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE). Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of Find the curl of A = (y cos ax)i + (y + ex)ka)2i – ex j – cos ax kb)i – ex j – cos ax kc)2i – ex j + cos ax kd)i – ex j + cos ax kCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Find the curl of A = (y cos ax)i + (y + ex)ka)2i – ex j – cos ax kb)i – ex j – cos ax kc)2i – ex j + cos ax kd)i – ex j + cos ax kCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Find the curl of A = (y cos ax)i + (y + ex)ka)2i – ex j – cos ax kb)i – ex j – cos ax kc)2i – ex j + cos ax kd)i – ex j + cos ax kCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Find the curl of A = (y cos ax)i + (y + ex)ka)2i – ex j – cos ax kb)i – ex j – cos ax kc)2i – ex j + cos ax kd)i – ex j + cos ax kCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Find the curl of A = (y cos ax)i + (y + ex)ka)2i – ex j – cos ax kb)i – ex j – cos ax kc)2i – ex j + cos ax kd)i – ex j + cos ax kCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
| Explore Courses for Electrical Engineering (EE) exam | |
Top Courses for Electrical Engineering (EE)
Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
