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At 373k and 1atm if density of liquid water is 1gm/ml and that of watervapour is 0.0006gm/ml then the volume occupied by molecules in 1 litre of stream at that temperature is. 1. 6ml 2. 60ml 3. 0.6ml 4. 0.06ml?
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For certain substances such as ammonium chloride, nitrogen peroxide, phosphorus pentachloride, etc. the measured densities are found to be less than those calculatedfrom their molecular formula. The observed densities decrease towards a limit as thetemperature is raised. This is due to the splitting of the molecules into simpler ones. The process is reversible and is called thermal dissociation.Examples :With increase in the number of molecules, the volume increases (pressure remaining constant) and, in consequence, the density decreases. As the temperature rises, more and more dissociation takes place, and when practically complete dissociation occursthe density reaches its lowest limit.The extent of issociation, ice., the fraction of the total number of molecules which suffers dissociation is called the degree of dissociation. Gas density measurements can be used to determine the degree of dissociation. Let us take by general case where one molecule of a substance A splits up into n molecule of B on heating; i.e.,t = 0 at = teq a x nx Total no. of moles Observed molecular weight or molar mass of the mixtureQ.If the total mass of the mixture in the above case is 300 gm, the moles at C(g) present are.

For certain substances such as ammonium chloride, nitrogen peroxide, phosphorus pentachloride, etc. the measured densities are found to be less than those calculatedfrom their molecular formula. The observed densities decrease towards a limit as thetemperature is raised. This is due to the splitting of the molecules into simpler ones. The process is reversible and is called thermal dissociation.Examples :With increase in the number of molecules, the volume increases (pressure remaining constant) and, in consequence, the density decreases. As the temperature rises, more and more dissociation takes place, and when practically complete dissociation occursthe density reaches its lowest limit.The extent of issociation, ice., the fraction of the total number of molecules which suffers dissociation is called the degree of dissociation. Gas density measurements can be used to determine the degree of dissociation. Let us take by general case where one molecule of a substance A splits up into n molecule of B on heating; i.e.,t = 0 at = teq a x nx Total no. of moles Observed molecular weight or molar mass of the mixtureQ.The K for the reaction is 640 mm at 775 K. The percentage dissociation of N2O4 at equilibrium pressure of 160 mm is

A system of greater disorder of molecules is more probable. The disorder of molecules is reflected by the entropy of the system. A liquid vaporizes to form a more disordered gas. When a solulte is present , there is additional contribution to the entropy of the liquid due to increase randomness. As the entropy of solution is higher than that of pure liquid, there is weaker tendency to form the gas.Thus , a solute (non volatil e) lowers the vapour pressure of a liquid, and hence a higher booing point of the solution Similarly, the greater randomness of the solution opposes the tendency to freeze. In consequence, a lower the temperature must be reached for achieving the equilibrium between the solid (frozen solvent) and the solution . Elevation of B.Pt. Tband depression of F.Pt. Tfof a solution are the colligative properties which depend only on the concentration of particles of the solute, not their identity.For dilute solutions, Tband Tfare proportional to the molality of the solute in the solution.The vaues of Kb and Kf do depend on the properties of the solvent. For liquids, is almost constant . [Troutans Rule , this constant for most of the Unassociated liquids (not having any strong bonding like Hydrogen bonding in the liquid state) is equal to 90J/mol. ] For solutes undergoing change of molecular state is solution (ionization or association), the observed T values differ from the calculate ones using the above relations. In such situations, the relationships are modified as Where i = Vant Hoff factor, greater than unity for ionization and smaller than unity for association of the solute molecules.Q.A mixture of two immiscible liquids at a constant pressure of 1 atm boils at a temperature

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?At 373k and 1atm if density of liquid water is 1gm/ml and that of watervapour is 0.0006gm/ml then the volume occupied by molecules in 1 litre of stream at that temperature is. 1. 6ml 2. 60ml 3. 0.6ml 4. 0.06ml?
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?At 373k and 1atm if density of liquid water is 1gm/ml and that of watervapour is 0.0006gm/ml then the volume occupied by molecules in 1 litre of stream at that temperature is. 1. 6ml 2. 60ml 3. 0.6ml 4. 0.06ml? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about ?At 373k and 1atm if density of liquid water is 1gm/ml and that of watervapour is 0.0006gm/ml then the volume occupied by molecules in 1 litre of stream at that temperature is. 1. 6ml 2. 60ml 3. 0.6ml 4. 0.06ml? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for ?At 373k and 1atm if density of liquid water is 1gm/ml and that of watervapour is 0.0006gm/ml then the volume occupied by molecules in 1 litre of stream at that temperature is. 1. 6ml 2. 60ml 3. 0.6ml 4. 0.06ml?.
Solutions for ?At 373k and 1atm if density of liquid water is 1gm/ml and that of watervapour is 0.0006gm/ml then the volume occupied by molecules in 1 litre of stream at that temperature is. 1. 6ml 2. 60ml 3. 0.6ml 4. 0.06ml? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of ?At 373k and 1atm if density of liquid water is 1gm/ml and that of watervapour is 0.0006gm/ml then the volume occupied by molecules in 1 litre of stream at that temperature is. 1. 6ml 2. 60ml 3. 0.6ml 4. 0.06ml? defined & explained in the simplest way possible. Besides giving the explanation of ?At 373k and 1atm if density of liquid water is 1gm/ml and that of watervapour is 0.0006gm/ml then the volume occupied by molecules in 1 litre of stream at that temperature is. 1. 6ml 2. 60ml 3. 0.6ml 4. 0.06ml?, a detailed solution for ?At 373k and 1atm if density of liquid water is 1gm/ml and that of watervapour is 0.0006gm/ml then the volume occupied by molecules in 1 litre of stream at that temperature is. 1. 6ml 2. 60ml 3. 0.6ml 4. 0.06ml? has been provided alongside types of ?At 373k and 1atm if density of liquid water is 1gm/ml and that of watervapour is 0.0006gm/ml then the volume occupied by molecules in 1 litre of stream at that temperature is. 1. 6ml 2. 60ml 3. 0.6ml 4. 0.06ml? theory, EduRev gives you an ample number of questions to practice ?At 373k and 1atm if density of liquid water is 1gm/ml and that of watervapour is 0.0006gm/ml then the volume occupied by molecules in 1 litre of stream at that temperature is. 1. 6ml 2. 60ml 3. 0.6ml 4. 0.06ml? tests, examples and also practice JEE tests.
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