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Starting with one mole of a compound A it is found that the reaction is 3/4th complete in one hour. If the reaction is first order, the rate constant is:
- a)2.31 min–1
- b)231 min–1
- c)0231 min–1
- d)00231 min–1
Correct answer is option 'C'. Can you explain this answer?
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Starting with one mole of a compound A it is found that the reaction i...
First draw a Lewis structure of each molecule, then consider the hybridization of the atoms other than H. For hybridization, see pp. 28-30.
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Starting with one mole of a compound A it is found that the reaction i...
Understanding the Reaction Completion
Starting with one mole of compound A, the reaction is 3/4th complete in one hour. This means that 0.75 moles of A have reacted, leaving 0.25 moles unreacted.
Calculating the Remaining Concentration
- Initial concentration of A = 1 mole
- Concentration after 1 hour = 1 - 0.75 = 0.25 moles
Rate Law for First-Order Reactions
For a first-order reaction, the rate law is given by:
- Rate = k[A]
The integrated rate equation is:
- ln([A]₀ / [A]) = kt
Where:
- [A]₀ = initial concentration
- [A] = concentration at time t
- k = rate constant
- t = time in appropriate units
Substituting the Values
- [A]₀ = 1 mole
- [A] after 1 hour = 0.25 moles
- t = 1 hour = 60 minutes
Now substituting into the equation:
- ln(1 / 0.25) = k * 60
Calculating the Logarithm
- ln(4) = k * 60
- ln(4) ≈ 1.386
Now, solving for k:
- k = 1.386 / 60 ≈ 0.0231 min⁻¹
Conclusion
Thus, the rate constant k is approximately 0.0231 min⁻¹, which corresponds to option 'C'.
Starting with one mole of compound A, the reaction is 3/4th complete in one hour. This means that 0.75 moles of A have reacted, leaving 0.25 moles unreacted.
Calculating the Remaining Concentration
- Initial concentration of A = 1 mole
- Concentration after 1 hour = 1 - 0.75 = 0.25 moles
Rate Law for First-Order Reactions
For a first-order reaction, the rate law is given by:
- Rate = k[A]
The integrated rate equation is:
- ln([A]₀ / [A]) = kt
Where:
- [A]₀ = initial concentration
- [A] = concentration at time t
- k = rate constant
- t = time in appropriate units
Substituting the Values
- [A]₀ = 1 mole
- [A] after 1 hour = 0.25 moles
- t = 1 hour = 60 minutes
Now substituting into the equation:
- ln(1 / 0.25) = k * 60
Calculating the Logarithm
- ln(4) = k * 60
- ln(4) ≈ 1.386
Now, solving for k:
- k = 1.386 / 60 ≈ 0.0231 min⁻¹
Conclusion
Thus, the rate constant k is approximately 0.0231 min⁻¹, which corresponds to option 'C'.
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Starting with one mole of a compound A it is found that the reaction is 3/4th complete in one hour. If the reaction is first order, the rate constant is:a)2.31 min–1b)231 min–1c)0231 min–1d)00231 min–1Correct answer is option 'C'. Can you explain this answer?
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Starting with one mole of a compound A it is found that the reaction is 3/4th complete in one hour. If the reaction is first order, the rate constant is:a)2.31 min–1b)231 min–1c)0231 min–1d)00231 min–1Correct answer is option 'C'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Starting with one mole of a compound A it is found that the reaction is 3/4th complete in one hour. If the reaction is first order, the rate constant is:a)2.31 min–1b)231 min–1c)0231 min–1d)00231 min–1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Starting with one mole of a compound A it is found that the reaction is 3/4th complete in one hour. If the reaction is first order, the rate constant is:a)2.31 min–1b)231 min–1c)0231 min–1d)00231 min–1Correct answer is option 'C'. Can you explain this answer?.
Starting with one mole of a compound A it is found that the reaction is 3/4th complete in one hour. If the reaction is first order, the rate constant is:a)2.31 min–1b)231 min–1c)0231 min–1d)00231 min–1Correct answer is option 'C'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Starting with one mole of a compound A it is found that the reaction is 3/4th complete in one hour. If the reaction is first order, the rate constant is:a)2.31 min–1b)231 min–1c)0231 min–1d)00231 min–1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Starting with one mole of a compound A it is found that the reaction is 3/4th complete in one hour. If the reaction is first order, the rate constant is:a)2.31 min–1b)231 min–1c)0231 min–1d)00231 min–1Correct answer is option 'C'. Can you explain this answer?.
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Starting with one mole of a compound A it is found that the reaction is 3/4th complete in one hour. If the reaction is first order, the rate constant is:a)2.31 min–1b)231 min–1c)0231 min–1d)00231 min–1Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Starting with one mole of a compound A it is found that the reaction is 3/4th complete in one hour. If the reaction is first order, the rate constant is:a)2.31 min–1b)231 min–1c)0231 min–1d)00231 min–1Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Starting with one mole of a compound A it is found that the reaction is 3/4th complete in one hour. If the reaction is first order, the rate constant is:a)2.31 min–1b)231 min–1c)0231 min–1d)00231 min–1Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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