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Fe2S3 5O2 gives 2Fe2So4 So2 equivalent weight of Fe2S3?
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Fe2S3 5O2 gives 2Fe2So4 So2 equivalent weight of Fe2S3?
Reaction: Fe2S3 + 5O2 → 2Fe2SO4 + 3SO2
Equivalent weight: The equivalent weight of a substance is the mass of the substance that reacts with or is equivalent to one mole of hydrogen ions (H+) or one mole of electrons (e-).
Calculating the equivalent weight of Fe2S3:
To determine the equivalent weight of Fe2S3, we need to consider its role in the reaction.
Step 1: Calculate the molar mass of Fe2S3.
Fe2S3 consists of 2 iron atoms (Fe) and 3 sulfur atoms (S). The atomic masses of Fe and S are 55.85 g/mol and 32.06 g/mol, respectively.
Molar mass of Fe2S3 = (2 * 55.85 g/mol) + (3 * 32.06 g/mol) = 159.82 g/mol
Step 2: Determine the moles of Fe2S3 reacting.
Using the stoichiometry of the balanced equation, we can see that 1 mole of Fe2S3 reacts to produce 2 moles of Fe2SO4.
Step 3: Calculate the equivalent weight of Fe2S3.
The equivalent weight is the mass of the substance that reacts with or is equivalent to one mole of electrons or hydrogen ions.
Equivalent weight of Fe2S3 = Molar mass of Fe2S3 / Moles of Fe2S3 reacting
To calculate the moles of Fe2S3 reacting, we need to consider the stoichiometry of the balanced equation. From the equation, we can see that 1 mole of Fe2S3 reacts to produce 2 moles of Fe2SO4.
Therefore, Moles of Fe2S3 reacting = 2 moles of Fe2SO4
Now, we can calculate the equivalent weight:
Equivalent weight of Fe2S3 = 159.82 g/mol / 2 = 79.91 g/mol
Therefore, the equivalent weight of Fe2S3 is 79.91 g/mol.
Explanation:
Fe2S3 is a reactant in the given chemical equation. The stoichiometry of the equation tells us that 1 mole of Fe2S3 reacts to produce 2 moles of Fe2SO4. The equivalent weight of Fe2S3 is calculated by dividing its molar mass by the number of moles of Fe2S3 reacting.
By following the steps outlined above, we find that the equivalent weight of Fe2S3 is 79.91 g/mol. This means that 79.91 grams of Fe2S3 is equivalent to one mole of electrons or hydrogen ions.
The equivalent weight is an important concept in stoichiometry and allows us to determine the amount of a substance needed or produced in a chemical reaction.
Equivalent weight: The equivalent weight of a substance is the mass of the substance that reacts with or is equivalent to one mole of hydrogen ions (H+) or one mole of electrons (e-).
Calculating the equivalent weight of Fe2S3:
To determine the equivalent weight of Fe2S3, we need to consider its role in the reaction.
Step 1: Calculate the molar mass of Fe2S3.
Fe2S3 consists of 2 iron atoms (Fe) and 3 sulfur atoms (S). The atomic masses of Fe and S are 55.85 g/mol and 32.06 g/mol, respectively.
Molar mass of Fe2S3 = (2 * 55.85 g/mol) + (3 * 32.06 g/mol) = 159.82 g/mol
Step 2: Determine the moles of Fe2S3 reacting.
Using the stoichiometry of the balanced equation, we can see that 1 mole of Fe2S3 reacts to produce 2 moles of Fe2SO4.
Step 3: Calculate the equivalent weight of Fe2S3.
The equivalent weight is the mass of the substance that reacts with or is equivalent to one mole of electrons or hydrogen ions.
Equivalent weight of Fe2S3 = Molar mass of Fe2S3 / Moles of Fe2S3 reacting
To calculate the moles of Fe2S3 reacting, we need to consider the stoichiometry of the balanced equation. From the equation, we can see that 1 mole of Fe2S3 reacts to produce 2 moles of Fe2SO4.
Therefore, Moles of Fe2S3 reacting = 2 moles of Fe2SO4
Now, we can calculate the equivalent weight:
Equivalent weight of Fe2S3 = 159.82 g/mol / 2 = 79.91 g/mol
Therefore, the equivalent weight of Fe2S3 is 79.91 g/mol.
Explanation:
Fe2S3 is a reactant in the given chemical equation. The stoichiometry of the equation tells us that 1 mole of Fe2S3 reacts to produce 2 moles of Fe2SO4. The equivalent weight of Fe2S3 is calculated by dividing its molar mass by the number of moles of Fe2S3 reacting.
By following the steps outlined above, we find that the equivalent weight of Fe2S3 is 79.91 g/mol. This means that 79.91 grams of Fe2S3 is equivalent to one mole of electrons or hydrogen ions.
The equivalent weight is an important concept in stoichiometry and allows us to determine the amount of a substance needed or produced in a chemical reaction.
Community Answer
Fe2S3 5O2 gives 2Fe2So4 So2 equivalent weight of Fe2S3?
Ans : M/22
N factor will be 22
N = 2*3 + 2*6+1*4 =22
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Fe2S3 5O2 gives 2Fe2So4 So2 equivalent weight of Fe2S3? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Fe2S3 5O2 gives 2Fe2So4 So2 equivalent weight of Fe2S3? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Fe2S3 5O2 gives 2Fe2So4 So2 equivalent weight of Fe2S3?.
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