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A player kicks a ball of mass250g at the centrr of the field. The ball leaves his foot with a speed of 10m/s find the work done by the player on the ball
Verified Answer
A player kicks a ball of mass250g at the centrr of the field. The ball...
The ball, which is initially at rest, gains kinetic energy due to work done on it by the player.
Thus, the work done by the player on the ball, W = kinetic energy (Ek) of the ball as it leaves his foot, i.e.,
W = Ek = mv2
Here, m = 250 g = 0.25 kg, v = 10 m/s
W = (0.25kg) (10 m/s)^2 = 12.5 J
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Most Upvoted Answer
A player kicks a ball of mass250g at the centrr of the field. The ball...
We know that:-Work done=kinetic energySo,K.E=1/2mv^2Therefore,W.D=1/2×25/100×100=12.5J
Community Answer
A player kicks a ball of mass250g at the centrr of the field. The ball...
To find the work done by the player on the ball, we can use the equation:

Work = Force × Distance

In this case, the force applied by the player on the ball is equal to the change in momentum of the ball. Since the ball is initially at rest, the change in momentum is equal to the momentum of the ball after being kicked. The momentum of an object is given by the equation:

Momentum = Mass × Velocity

Given that the mass of the ball is 250g (or 0.25kg) and the velocity is 10m/s, we can calculate the momentum:

Momentum = 0.25kg × 10m/s = 2.5kg·m/s

Therefore, the force applied by the player on the ball is 2.5kg·m/s.

Now, we need to find the distance over which this force is applied. Since the ball is kicked at the center of the field, we can assume that the distance traveled by the ball is the radius of the field. Let's say the radius of the field is R meters.

So, the work done by the player on the ball is:

Work = Force × Distance = 2.5kg·m/s × R meters

We can't determine the exact value of R without more information, but we can see that the work done by the player depends on the radius of the field.
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