Potential energy of an electron in hydrogen atom is -3.02 eV it's kine...
Calculating Kinetic Energy of an Electron in Hydrogen Atom
Understanding Potential Energy of an Electron in Hydrogen Atom
In a hydrogen atom, the potential energy of an electron is given by the equation:
Potential Energy = -13.6/n^2 eV
Where n is the principal quantum number of the electron.
For the ground state of hydrogen atom, n = 1. Therefore, the potential energy of an electron in the ground state of hydrogen atom is:
Potential Energy = -13.6/1^2 = -13.6 eV
However, the question states that the potential energy of the electron is -3.02 eV. This means that the electron is not in the ground state, but in an excited state.
Calculating Kinetic Energy of an Electron in Hydrogen Atom
The total energy of an electron in a hydrogen atom is given by the equation:
Total Energy = Kinetic Energy + Potential Energy
Therefore, the kinetic energy of the electron can be calculated by rearranging the equation:
Kinetic Energy = Total Energy - Potential Energy
For the ground state of hydrogen atom, the total energy is -13.6 eV. Therefore, the kinetic energy of the electron in the ground state is:
Kinetic Energy = -13.6 eV - (-13.6 eV) = 0 eV
However, for an electron with a potential energy of -3.02 eV, the total energy is:
Total Energy = Kinetic Energy + Potential Energy
Total Energy = Kinetic Energy - 3.02 eV
Since the electron is still bound to the nucleus, its total energy must be negative. Therefore, the kinetic energy of the electron must be:
Kinetic Energy = Total Energy + 3.02 eV
Kinetic Energy = -3.02 eV + 3.02 eV = 0 eV
Therefore, the kinetic energy of an electron in an excited state of hydrogen atom is also 0 eV.