A gaseous mixture of three gases A,B and C has pressure of 10 atm the ...
I think the answer is 12 gm.
Partial pressure of a gas is directly proportional to number of moles of the constituent gas. In this way, the ....Number of moles of C = Partial pressure of C= 6
No. Of moles=mass/gram molecular weightmass= 6*2=12gm
A gaseous mixture of three gases A,B and C has pressure of 10 atm the ...
Calculation of Weight of Gas C in the Mixture:
- First, calculate the total moles of gas C in the mixture.
- Next, determine the moles of gas C using the ideal gas law.
- Finally, calculate the weight of gas C using its molecular weight.
Step 1: Calculate the Total Moles of Gas C
- Given that the total number of moles of all gases is 10, and the moles of gases A and B are not provided.
- Let's assume the moles of gas C be x.
- Therefore, the total moles can be expressed as: x + moles of A + moles of B = 10
Step 2: Determine the Moles of Gas C
- Using the ideal gas law equation: PV = nRT, where P is the partial pressure of gas C (given as 10 atm), V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
- Since the volume and temperature are not provided, we can assume them to be constant.
- Therefore, nC = PC / RT
Step 3: Calculate the Weight of Gas C
- The molecular weight of gas C is given as 2 g/mol.
- The weight of gas C can be calculated using the formula: Weight = Moles x Molecular Weight
- Substituting the values, the weight of gas C in grams can be determined.
By following these steps, the weight of gas C in grams present in the mixture can be accurately calculated based on the given information.
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.