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If 9x²+ 1/9x² = 16 find the value of a) 3x+ 1/3x b) 3x-1/3x? Using identities solve my question?
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If 9x²+ 1/9x² = 16 find the value of a) 3x+ 1/3x b) 3x-1/3x? Using ide...
A. (3x+1/3x)²= (3x)²+(1/3x)²+2X3xX1/3x
= 9x²+1/9x²+2
= 16+2
(3x+1/3x)² = 18
3x+1/3x=√18

b. (3x-1/3x)²= (3x)²+(1/3x)²-2X3xX1/3x
= 9x²+1/9x²-2
=16-2
(3x-1/3x)²=14
3x-1/3x. =√14
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