Consider the following two curves in thex-yplaney = x3+ x2+ 5y = x2+ x...
y=x³ + x² + 5
y = x² + x + 5
We equate each other.
x³ + x² + 5 = x² + x + 5
Subtract x² both the side
x³ + 5 = x + 5
Subtract 5 both the side
x³ = x
x³ - x = 0
x(x² - 1) = 0
x(x + 1)(x - 1) = 0
We get
x = 0 & x - 1 = 0 & x + 1 = 0
x = 0, x = 1 & x = -1
We get the three values of x in interval [-2,2]
So, both the curves cuts each other exactly three times.
Consider the following two curves in thex-yplaney = x3+ x2+ 5y = x2+ x...
To determine which statement is true for the given curves, we need to find their points of intersection.
Setting the equations equal to each other, we have:
x^3 + x^2 - 5y = x^2 + x - 5
Simplifying, we get:
x^3 - 6y = 0
This equation represents a curve with a single branch. To find its points of intersection with the y-axis, we set x = 0:
0 - 6y = 0
y = 0
Thus, the curve intersects the y-axis at the point (0,0).
Next, let's find the points of intersection with the x-axis. Setting y = 0, we have:
x^3 - 6(0) = 0
x^3 = 0
x = 0
Therefore, the curve also intersects the x-axis at the point (0,0).
Since both curves intersect at the point (0,0), the statement "The curves intersect at a single point." is true.