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2^37 is divided by 223 then remainder is??
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2^37 is divided by 223 then remainder is??
Dividing 2^37 by 223 to find the remainder:
The remainder when dividing 2^37 by 223 can be calculated using the concept of modular arithmetic.

Step 1: Expressing 2^37 as a congruence modulo 223
- We can express 2^37 as (2^5)^7 = 32^7
- Since 32 ≡ -2 (mod 223), we have 2^37 ≡ (-2)^7 (mod 223)

Step 2: Calculating (-2)^7 mod 223
- (-2)^7 = -128
- To find the remainder when dividing -128 by 223, we need to consider the positive equivalent of -128 which is 223 - 128 = 95

Step 3: Final Result
- Therefore, the remainder when dividing 2^37 by 223 is 95.
In conclusion, when 2^37 is divided by 223, the remainder is 95. This calculation involves using modular arithmetic to find the equivalent positive value within the modulus.
Community Answer
2^37 is divided by 223 then remainder is??
You should use log here...basic method requires knowing characteristic
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2^37 is divided by 223 then remainder is??
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