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In a coaxial, straight cable, the central conductor and the outer conductor carry equal currents in opposite directions. The magnetic field is zero.
  • a)
    outside the cable
  • b)
    inside the inner conductor
  • c)
    inside the outer conductor
  • d)
    in between the two conductors
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In a coaxial, straight cable, the central conductor and the outer cond...
Construct an Ampere’s loop in the concerned regions to see the value of ip.
 At a pont outside the co-axial tube at a diatance R from the central axis consider a circular path.
Then from Amperes Law closed integral of B.dl=μ0I(net)
but the net current is zero as the current in the two cables flow in opposite directions.
therefore Magnetic field is zero outside
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Most Upvoted Answer
In a coaxial, straight cable, the central conductor and the outer cond...
B=Bouter+Binner
Since the current carried by the outer and inner are equal and in opposite direction,
magnetic field produced by the cylinders at a point P (distance r from central axis) is
Bouter= (μ0/4π)i(dl×r/r3)
Binner=−(μ0/4π)i(dl×r/r3)
∴B=Bouter+Binner=0
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In a coaxial, straight cable, the central conductor and the outer conductor carry equal currents in opposite directions. The magnetic field is zero.a)outside the cableb)inside the inner conductorc)inside the outer conductord)in between the two conductorsCorrect answer is option 'A'. Can you explain this answer?
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