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An object of mass 100 kg is accelerated uniformly from a velocity of 5 m/s to 8 m/s in 6s. Calculate:
(1)the initial and final momentum of the object
(2)the magnitude of the force exerted on the object?
(1)the initial and final momentum of the object
(2)the magnitude of the force exerted on the object?
Verified Answer
An object of mass 100 kg is accelerated uniformly from a velocity of 5...
Initial momentum=mass*initial velocity=(100*5)=500kg m/s
Final momentum=mass*final velocity=(100*8)=800 kg m/s
Force=Rate of change of momentum
Force=m(v-u)/t
=100(8-5)/6
=100*3/6=50 N
This question is part of UPSC exam. View all Class 9 courses
Most Upvoted Answer
An object of mass 100 kg is accelerated uniformly from a velocity of 5...
1. Initial and Final Momentum:
The momentum of an object is given by the product of its mass and velocity. The initial momentum of the object can be calculated using the formula:
Initial momentum = mass × initial velocity
Given that the mass of the object is 100 kg and the initial velocity is 5 m/s, we can substitute these values into the formula:
Initial momentum = 100 kg × 5 m/s = 500 kg·m/s
Similarly, the final momentum of the object can be calculated using the formula:
Final momentum = mass × final velocity
Given that the final velocity is 8 m/s, we can substitute the values into the formula:
Final momentum = 100 kg × 8 m/s = 800 kg·m/s
Therefore, the initial momentum of the object is 500 kg·m/s and the final momentum is 800 kg·m/s.
2. Magnitude of the Force Exerted:
The force exerted on an object can be determined using Newton's second law of motion, which states that the force acting on an object is equal to the rate of change of its momentum. Mathematically, this can be expressed as:
Force = change in momentum / time
In this case, the change in momentum is the difference between the final and initial momentum, and the time taken for this change is given as 6 seconds.
Change in momentum = Final momentum - Initial momentum
= 800 kg·m/s - 500 kg·m/s
= 300 kg·m/s
Now, substituting the values into the formula:
Force = change in momentum / time
= 300 kg·m/s / 6 s
= 50 N
Therefore, the magnitude of the force exerted on the object is 50 Newtons.
The momentum of an object is given by the product of its mass and velocity. The initial momentum of the object can be calculated using the formula:
Initial momentum = mass × initial velocity
Given that the mass of the object is 100 kg and the initial velocity is 5 m/s, we can substitute these values into the formula:
Initial momentum = 100 kg × 5 m/s = 500 kg·m/s
Similarly, the final momentum of the object can be calculated using the formula:
Final momentum = mass × final velocity
Given that the final velocity is 8 m/s, we can substitute the values into the formula:
Final momentum = 100 kg × 8 m/s = 800 kg·m/s
Therefore, the initial momentum of the object is 500 kg·m/s and the final momentum is 800 kg·m/s.
2. Magnitude of the Force Exerted:
The force exerted on an object can be determined using Newton's second law of motion, which states that the force acting on an object is equal to the rate of change of its momentum. Mathematically, this can be expressed as:
Force = change in momentum / time
In this case, the change in momentum is the difference between the final and initial momentum, and the time taken for this change is given as 6 seconds.
Change in momentum = Final momentum - Initial momentum
= 800 kg·m/s - 500 kg·m/s
= 300 kg·m/s
Now, substituting the values into the formula:
Force = change in momentum / time
= 300 kg·m/s / 6 s
= 50 N
Therefore, the magnitude of the force exerted on the object is 50 Newtons.
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An object of mass 100 kg is accelerated uniformly from a velocity of 5 m/s to 8 m/s in 6s. Calculate:(1)the initial and final momentum of the object(2)the magnitude of the force exerted on the object?
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An object of mass 100 kg is accelerated uniformly from a velocity of 5 m/s to 8 m/s in 6s. Calculate:(1)the initial and final momentum of the object(2)the magnitude of the force exerted on the object? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about An object of mass 100 kg is accelerated uniformly from a velocity of 5 m/s to 8 m/s in 6s. Calculate:(1)the initial and final momentum of the object(2)the magnitude of the force exerted on the object? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object of mass 100 kg is accelerated uniformly from a velocity of 5 m/s to 8 m/s in 6s. Calculate:(1)the initial and final momentum of the object(2)the magnitude of the force exerted on the object?.
An object of mass 100 kg is accelerated uniformly from a velocity of 5 m/s to 8 m/s in 6s. Calculate:(1)the initial and final momentum of the object(2)the magnitude of the force exerted on the object? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about An object of mass 100 kg is accelerated uniformly from a velocity of 5 m/s to 8 m/s in 6s. Calculate:(1)the initial and final momentum of the object(2)the magnitude of the force exerted on the object? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object of mass 100 kg is accelerated uniformly from a velocity of 5 m/s to 8 m/s in 6s. Calculate:(1)the initial and final momentum of the object(2)the magnitude of the force exerted on the object?.
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