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An aeroplane weighing 63000 kg flies up from sea level to a height of 8000m it's engine run with pure Normal octane .As a 30% efficiency . calculate the fuel cost of flight if octane sells at Rs 3/l . Density of octane=0.705g/ml. And heat of combustion=1300Kcal/mol?
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An aeroplane weighing 63000 kg flies up from sea level to a height of ...
Calculation of Fuel Cost for Flight


Given Data:



  • Weight of the aeroplane = 63000 kg

  • Height to which it flies = 8000 m

  • Efficiency of the engine = 30%

  • Selling price of octane = Rs 3/l

  • Density of octane = 0.705 g/ml

  • Heat of combustion of octane = 1300 Kcal/mol



Calculation of Fuel Consumption:


The potential energy gained by the aeroplane on reaching a height of 8000 m can be calculated as:

Potential Energy = mgh
where m = mass of the aeroplane, g = acceleration due to gravity, and h = height

On substituting the given values, we get:

Potential Energy = 63000 x 9.8 x 8000
= 4.94 x 10^9 J

The actual energy required by the aeroplane can be calculated using the efficiency of the engine:

Actual Energy = Potential Energy / Efficiency
= 4.94 x 10^9 / 0.3
= 1.65 x 10^10 J

The number of moles of octane required to produce this energy can be calculated using the heat of combustion:

Number of Moles = Actual Energy / Heat of Combustion
= 1.65 x 10^10 / (1300 x 1000)
= 12.69 mol

The mass of octane required can be calculated using the density of octane:

Mass = Number of Moles x Molar Mass x Density
where Molar Mass of octane = 114.23 g/mol

On substituting the given values, we get:

Mass = 12.69 x 114.23 x 0.705
= 1004.38 g

The fuel cost can be calculated using the selling price of octane:

Fuel Cost = Mass x Selling Price / 1000
= 1004.38 x 3 / 1000
= Rs 3.01

Conclusion:


Thus, the fuel cost for the given flight is Rs 3.01.
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An aeroplane weighing 63000 kg flies up from sea level to a height of ...
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An aeroplane weighing 63000 kg flies up from sea level to a height of 8000m it's engine run with pure Normal octane .As a 30% efficiency . calculate the fuel cost of flight if octane sells at Rs 3/l . Density of octane=0.705g/ml. And heat of combustion=1300Kcal/mol?
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An aeroplane weighing 63000 kg flies up from sea level to a height of 8000m it's engine run with pure Normal octane .As a 30% efficiency . calculate the fuel cost of flight if octane sells at Rs 3/l . Density of octane=0.705g/ml. And heat of combustion=1300Kcal/mol? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about An aeroplane weighing 63000 kg flies up from sea level to a height of 8000m it's engine run with pure Normal octane .As a 30% efficiency . calculate the fuel cost of flight if octane sells at Rs 3/l . Density of octane=0.705g/ml. And heat of combustion=1300Kcal/mol? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An aeroplane weighing 63000 kg flies up from sea level to a height of 8000m it's engine run with pure Normal octane .As a 30% efficiency . calculate the fuel cost of flight if octane sells at Rs 3/l . Density of octane=0.705g/ml. And heat of combustion=1300Kcal/mol?.
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