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A sound source of frequency 600 Hz is moving towards an observer with velocity 20m/s. The speed of sound is 340m/s. The frequency heard by observer will be
- a)630.5hz
- b)30hz
- c)637.5hz
- d)63.5 Hz
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A sound source of frequency 600 Hz is moving towards an observer with ...
F(s)/F(l) = [V+V(s)]/[V+V(l)]
V = velocity of sound = 340m/s
V(l) = velocity of listener = 0
F(l) = frequency heard by listener = ?
V(s) = velocity of source = -20m/s (because, it's source to listener)
F(s) = frequency of source = 600hz
By putting these values in the above formula and solving we get,
F(l) = 637.5 Hz.
Hence C is correct.
V = velocity of sound = 340m/s
V(l) = velocity of listener = 0
F(l) = frequency heard by listener = ?
V(s) = velocity of source = -20m/s (because, it's source to listener)
F(s) = frequency of source = 600hz
By putting these values in the above formula and solving we get,
F(l) = 637.5 Hz.
Hence C is correct.
Most Upvoted Answer
A sound source of frequency 600 Hz is moving towards an observer with ...
Given:
Frequency of sound source = 600 Hz
Velocity of sound = 340 m/s
Velocity of observer = 20 m/s
The frequency heard by observer = ?
Formula used:
The formula used to find the frequency heard by an observer when both the sound source and observer are in motion is given by:
f' = f ((v+u)/(v±vs))
where,
f' = Frequency heard by the observer
f = Frequency of sound source
v = Velocity of sound
u = Velocity of observer
vs = Velocity of sound in the medium
Calculation:
Given, f = 600 Hz
v = 340 m/s
u = 20 m/s
vs = v
Using the above formula,
f' = f ((v+u)/(v±vs))
f' = 600 ((340+20)/(340±340))
f' = 600 ((360)/(0))
As the denominator is zero, we use the positive sign in the denominator as the observer is moving towards the sound source.
f' = 600 x 360/340
f' = 637.5 Hz
Hence, the frequency heard by the observer is 637.5 Hz.
Therefore, the correct answer is option (c) 637.5 Hz.
Frequency of sound source = 600 Hz
Velocity of sound = 340 m/s
Velocity of observer = 20 m/s
The frequency heard by observer = ?
Formula used:
The formula used to find the frequency heard by an observer when both the sound source and observer are in motion is given by:
f' = f ((v+u)/(v±vs))
where,
f' = Frequency heard by the observer
f = Frequency of sound source
v = Velocity of sound
u = Velocity of observer
vs = Velocity of sound in the medium
Calculation:
Given, f = 600 Hz
v = 340 m/s
u = 20 m/s
vs = v
Using the above formula,
f' = f ((v+u)/(v±vs))
f' = 600 ((340+20)/(340±340))
f' = 600 ((360)/(0))
As the denominator is zero, we use the positive sign in the denominator as the observer is moving towards the sound source.
f' = 600 x 360/340
f' = 637.5 Hz
Hence, the frequency heard by the observer is 637.5 Hz.
Therefore, the correct answer is option (c) 637.5 Hz.
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Community Answer
A sound source of frequency 600 Hz is moving towards an observer with ...
Frequency heard by observer = apparent frequency= original frequency (V-Vobs) divided by V-Vs
V velocity of sound
Vobs Velocity of observer
Vs Velocity of source
V velocity of sound
Vobs Velocity of observer
Vs Velocity of source
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