Question Description
Ethyl chloride (C2H5Cl), is prepared by reaction of ethylene with hydrogen chloride :C2H4(g) + HCl (g) → C2H5cl(g) ΔH = -72.3 kJWhat is the value of ΔE (in kJ), if 70 g of ethylene and 73 g of HCl are allowed to react at 300 K.a)-69.8b)-180.75c)-174.5d)-139.6Correct answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared
according to
the Class 11 exam syllabus. Information about Ethyl chloride (C2H5Cl), is prepared by reaction of ethylene with hydrogen chloride :C2H4(g) + HCl (g) → C2H5cl(g) ΔH = -72.3 kJWhat is the value of ΔE (in kJ), if 70 g of ethylene and 73 g of HCl are allowed to react at 300 K.a)-69.8b)-180.75c)-174.5d)-139.6Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for Ethyl chloride (C2H5Cl), is prepared by reaction of ethylene with hydrogen chloride :C2H4(g) + HCl (g) → C2H5cl(g) ΔH = -72.3 kJWhat is the value of ΔE (in kJ), if 70 g of ethylene and 73 g of HCl are allowed to react at 300 K.a)-69.8b)-180.75c)-174.5d)-139.6Correct answer is option 'D'. Can you explain this answer?.
Solutions for Ethyl chloride (C2H5Cl), is prepared by reaction of ethylene with hydrogen chloride :C2H4(g) + HCl (g) → C2H5cl(g) ΔH = -72.3 kJWhat is the value of ΔE (in kJ), if 70 g of ethylene and 73 g of HCl are allowed to react at 300 K.a)-69.8b)-180.75c)-174.5d)-139.6Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of Ethyl chloride (C2H5Cl), is prepared by reaction of ethylene with hydrogen chloride :C2H4(g) + HCl (g) → C2H5cl(g) ΔH = -72.3 kJWhat is the value of ΔE (in kJ), if 70 g of ethylene and 73 g of HCl are allowed to react at 300 K.a)-69.8b)-180.75c)-174.5d)-139.6Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Ethyl chloride (C2H5Cl), is prepared by reaction of ethylene with hydrogen chloride :C2H4(g) + HCl (g) → C2H5cl(g) ΔH = -72.3 kJWhat is the value of ΔE (in kJ), if 70 g of ethylene and 73 g of HCl are allowed to react at 300 K.a)-69.8b)-180.75c)-174.5d)-139.6Correct answer is option 'D'. Can you explain this answer?, a detailed solution for Ethyl chloride (C2H5Cl), is prepared by reaction of ethylene with hydrogen chloride :C2H4(g) + HCl (g) → C2H5cl(g) ΔH = -72.3 kJWhat is the value of ΔE (in kJ), if 70 g of ethylene and 73 g of HCl are allowed to react at 300 K.a)-69.8b)-180.75c)-174.5d)-139.6Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of Ethyl chloride (C2H5Cl), is prepared by reaction of ethylene with hydrogen chloride :C2H4(g) + HCl (g) → C2H5cl(g) ΔH = -72.3 kJWhat is the value of ΔE (in kJ), if 70 g of ethylene and 73 g of HCl are allowed to react at 300 K.a)-69.8b)-180.75c)-174.5d)-139.6Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Ethyl chloride (C2H5Cl), is prepared by reaction of ethylene with hydrogen chloride :C2H4(g) + HCl (g) → C2H5cl(g) ΔH = -72.3 kJWhat is the value of ΔE (in kJ), if 70 g of ethylene and 73 g of HCl are allowed to react at 300 K.a)-69.8b)-180.75c)-174.5d)-139.6Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 11 tests.