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Give the family f lines, a(2x + y + 4) + b(x – 2y – 3) = 0.amongteh lines of the family, the number of lines situated at a distance of √10 from the point M(2, -3) is 
  • a)
    0
  • b)
    1
  • c)
    2
  • d)
    ∞
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Give the family f lines, a(2x + y + 4) + b(x – 2y – 3) = 0...
The point of intersection of the two lines are (-1,- 2).
Distance PM = √10
Hence the required line is one which passes through (-1, -2) and is perpendicular to P.M.
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Give the family f lines, a(2x + y + 4) + b(x – 2y – 3) = 0...
2y 3) c(3x 2y 5) d(4x 3y 6).
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The ciliary muscles of eye control the curvature of the lens in the eye and hence can alter the effective focal length of the system. When the muscles are fully relaxed, the focal length is maximum. When the muscles are strained the curvature of lens increases (that means radius of curvature decreases) and focal length decreases. For a clear vision the image must be on retina. The image distance is therefore fixed for clear vision and it equals the distance of retina from eye-lens. It is about 2.5 cm for a grown-up person.A person can theoretically have clear vision of objects situated at any large distance from the eye. The smallest distance at which a person can clearly see is related to minimum possible focal length. The ciliary muscles are most strained in this position. For an average grown-up person minimum distance of object should be around 25 cm.A person suffering from eye defects uses spectacles (Eye glass). The function of the lens of spectacles is to form the image of the objects within the range in which person can see clearly. The image of the spectacle-lens becomes object for eye-lens and whose image is formed on retina.The number of spectacle-lens used for the remedy of eye defect is decided by the power of the lens required and the number of spectacle-lens is equal to the numerical value of the power of lens with sign. For example power of lens required is +3D (converging lens of focal length 100/3 cm) then number of lens will be +3.For all the calculations required you can use the lens formula and lens makers formula. Assume that the eye lens is equiconvex lens. Neglect the distance between eye lens and the spectacle lens.Q.A nearsighted man can clearly see object only upto a distance of 100 cm and not beyond this. The number of the spectacles lens necessary for the remedy of this defect will be.

The ciliary muscles of eye control the curvature of the lens in the eye and hence can alter the effective focal length of the system. When the muscles are fully relaxed, the focal length is maximum. When the muscles are strained the curvature of lens increases (that means radius of curvature decreases) and focal length decreases. For a clear vision the image must be on retina. The image distance is therefore fixed for clear vision and it equals the distance of retina from eye-lens. It is about 2.5 cm for a grown-up person.A person can theoretically have clear vision of objects situated at any large distance from the eye. The smallest distance at which a person can clearly see is related to minimum possible focal length. The ciliary muscles are most strained in this position. For an average grown-up person minimum distance of object should be around 25 cm.A person suffering from eye defects uses spectacles (Eye glass). The function of the lens of spectacles is to form the image of the objects within the range in which person can see clearly. The image of the spectacle-lens becomes object for eye-lens and whose image is formed on retina.The number of spectacle-lens used for the remedy of eye defect is decided by the power of the lens required and the number of spectacle-lens is equal to the numerical value of the power of lens with sign. For example power of lens required is +3D (converging lens of focal length 100/3 cm) then number of lens will be +3.For all the calculations required you can use the lens formula and lens makers formula. Assume that the eye lens is equiconvex lens. Neglect the distance between eye lens and the spectacle lens.Q.Maximum focal length of eye lens of normal person is

The ciliary muscles of eye control the curvature of the lens in the eye and hence can alter the effective focal length of the system. When the muscles are fully relaxed, the focal length is maximum. When the muscles are strained the curvature of lens increases (that means radius of curvature decreases) and focal length decreases. For a clear vision the image must be on retina. The image distance is therefore fixed for clear vision and it equals the distance of retina from eye-lens. It is about 2.5 cm for a grown-up person.A person can theoretically have clear vision of objects situated at any large distance from the eye. The smallest distance at which a person can clearly see is related to minimum possible focal length. The ciliary muscles are most strained in this position. For an average grown-up person minimum distance of object should be around 25 cm.A person suffering from eye defects uses spectacles (Eye glass). The function of the lens of spectacles is to form the image of the objects within the range in which person can see clearly. The image of the spectacle-lens becomes object for eye-lens and whose image is formed on retina.The number of spectacle-lens used for the remedy of eye defect is decided by the power of the lens required and the number of spectacle-lens is equal to the numerical value of the power of lens with sign. For example power of lens required is +3D (converging lens of focal length100/3 cm) then number of lens will be +3.For all the calculations required you can use the lens formula and lens makers formula. Assume that the eye lens is equiconvex lens. Neglect the distance between eye lens and the spectacle lens.Q.Minimum focal length of eye lens of a normal person is

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Give the family f lines, a(2x + y + 4) + b(x – 2y – 3) = 0.amongteh lines of the family, the number of lines situated at a distance of√10from the point M(2, -3) isa)0b)1c)2d)∞Correct answer is option 'B'. Can you explain this answer?
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Give the family f lines, a(2x + y + 4) + b(x – 2y – 3) = 0.amongteh lines of the family, the number of lines situated at a distance of√10from the point M(2, -3) isa)0b)1c)2d)∞Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Give the family f lines, a(2x + y + 4) + b(x – 2y – 3) = 0.amongteh lines of the family, the number of lines situated at a distance of√10from the point M(2, -3) isa)0b)1c)2d)∞Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Give the family f lines, a(2x + y + 4) + b(x – 2y – 3) = 0.amongteh lines of the family, the number of lines situated at a distance of√10from the point M(2, -3) isa)0b)1c)2d)∞Correct answer is option 'B'. Can you explain this answer?.
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