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When an air bubble of radius R lies at a depth h below the free surface of a liquid of density ρ and surface tension Sla, then the excess pressure inside the bubble will be
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
When an air bubble of radius R lies at a depth h below the free surfac...
Excess pressure inside a cavity or air bubble in liquid formula
P[excess] = P[inside] - P [outside]
P [outside]  =P[atm]
P[inside]= P[atm] +hpg [here p represents density] +2T/R
P[excess] = P[atm] +hpg [here p represents density] +2T/R-P[atm]
P[excess] = hpg+2T/R
Now substitute value for T
P[excess] = hpg+2S/R
Hence C is correct.
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Most Upvoted Answer
When an air bubble of radius R lies at a depth h below the free surfac...
Excess pressure inside a cavity or air bubble in liquid
    formula  P[excess] = P[inside] - P [outside] 
      P [outside]  =P[atm]
      P[inside]= P[atm] +hpg [here p represents density] +2T/R
       P[excess] = P[atm] +hpg [here p represents density] +2T/R-P[atm]
       P[excess] = hpg+2T/R
now substitute vale for T 
   P[excess] = hpg+2
S
la
/R
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Community Answer
When an air bubble of radius R lies at a depth h below the free surfac...
Excess pressure inside a cavity or air bubble in liquid formula
P[excess] = P[inside] - P [outside]
P [outside]  =P[atm]
P[inside]= P[atm] +hpg [here p represents density] +2T/R
P[excess] = P[atm] +hpg [here p represents density] +2T/R-P[atm]
P[excess] = hpg+2T/R
Now substitute value for T
P[excess] = hpg+2S/R
Hence C is correct.
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