Current Drawn from Mains

To find the current drawn from the mains, we can use the formula:

Current (I) = Power (P) / Voltage (V)

First, let's calculate the total power consumed by the bulbs and tube lights.

Power of each bulb = 60 watts
Number of bulbs = 5
Total power consumed by the bulbs = 60 watts * 5 bulbs = 300 watts

Power of each tube light = 40 watts
Number of tube lights = 2
Total power consumed by the tube lights = 40 watts * 2 tube lights = 80 watts

Total power consumed by all the lights = 300 watts + 80 watts = 380 watts

Now, let's calculate the current drawn from the mains.

Voltage (V) = 220 volts (given)
Power (P) = 380 watts (calculated)

Using the formula, Current (I) = Power (P) / Voltage (V), we can substitute the values to find the current drawn.

Current (I) = 380 watts / 220 volts = 1.73 Amperes (approximately)

Therefore, the current drawn from the mains is approximately 1.73 Amperes.

Number of Additional Bulbs

To find the number of additional bulbs that can be lighted on a festival day, we need to consider the main fuse capacity and the power rating of the additional bulbs.

Main fuse capacity = 5 Amperes (given)
Power of each additional bulb = 100 watts (given)

The maximum total power that can be supported by the main fuse can be calculated using the formula:

Max Power = Main Fuse Capacity * Voltage

Max Power = 5 Amperes * 220 volts = 1100 watts

Now, let's calculate how much power is already being consumed by the existing lights.

Total power consumed by the existing lights = 380 watts (calculated)

Therefore, the remaining power capacity for additional bulbs is:

Remaining power capacity = Max Power - Total power consumed by existing lights
Remaining power capacity = 1100 watts - 380 watts = 720 watts

To find the number of additional bulbs that can be lighted, we need to divide the remaining power capacity by the power of each additional bulb.

Number of additional bulbs = Remaining power capacity / Power of each additional bulb
Number of additional bulbs = 720 watts / 100 watts = 7.2 bulbs

Since we cannot have a fraction of a bulb, we can only light up a whole number of additional bulbs. Therefore, the maximum number of additional bulbs that can be lighted on the festival day is 7.

Summary

- The current drawn from the mains is approximately 1.73 Amperes when 5 bulbs of 60 watts and 2 tube lights of 40 watts are used simultaneously.
- The number of additional bulbs that can be lighted on the festival day is 7, considering the main fuse capacity of 5 Amperes and each additional bulb having a power rating of 100 watts.