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a block of mass M and charge Q is connected to a point o with help of an inextensible string the system is on a horizontal table and electric field of intensity E is switched on in direction perpendicular to string what will be tension in a string when it become parallel to electric field.
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a block of mass M and charge Q is connected to a point o with help of ...
Problem:

A block of mass M and charge Q is connected to a point O with the help of an inextensible string. The system is on a horizontal table, and an electric field of intensity E is switched on in a direction perpendicular to the string. What will be the tension in the string when it becomes parallel to the electric field? Explain in detail.


Solution:


Initial Situation:



  • The block is on a horizontal table, and the string is attached to point O.

  • The electric field is perpendicular to the string.

  • The block has a charge Q.

  • The block is at rest.



Force on the block:



  • When the electric field is switched on, a force will act on the block due to its charge.

  • The force on the block will be F = QE, where Q is the charge on the block, and E is the electric field intensity.

  • The force will be perpendicular to the string.



Tension in the string:



  • Initially, the tension in the string is equal to the weight of the block, i.e., T = Mg, where M is the mass of the block and g is the acceleration due to gravity.

  • When the electric field is switched on, the tension in the string will increase due to the force acting on the block.

  • The tension in the string when it becomes parallel to the electric field can be calculated as follows:


    • Let θ be the angle between the string and the electric field.

    • When the string becomes parallel to the electric field, θ = 0.

    • At this point, the force on the block due to the electric field is F = QE.

    • The tension in the string can be calculated using the following equation:

    • T = Mg + Fsinθ = Mg + QEsinθ

    • Substituting θ = 0, we get:

    • T = Mg + QEsin0 = Mg + 0 = Mg


  • Therefore, the tension in the string when it becomes parallel to the electric field is equal to the weight of the block.



Conclusion:

The tension in the string when it becomes parallel to the electric field is equal to the weight of the block. This is because the force on the block due to the electric field is perpendicular to the direction of the string, and hence it does not contribute to the tension in the string.
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a block of mass M and charge Q is connected to a point o with help of ...
Is the answer is 2qE plz let me know that it is correct or not....
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a block of mass M and charge Q is connected to a point o with help of an inextensible string the system is on a horizontal table and electric field of intensity E is switched on in direction perpendicular to string what will be tension in a string when it become parallel to electric field.
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