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A flat plate 30mm wide and “t”mm wide is subjected to a tensile force of 5kN. The plate has a circular hole of diameter 15mm with the centre coinciding with the diagonal intersection point of the rectangle. If stress concentration factor=2.16, find the thickness of the plate if maximum allowable tensile stress is 80N/mm².
- a)8mm
- b)9mm
- c)10mm
- d)12mm
Correct answer is option 'B'. Can you explain this answer?
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A flat plate 30mm wide and “t”mm wide is subjected to a te...
Σ=P/ (w-d) x t or σ=5000/(30-15)xt ; σ(max)=K x σ or σ(max)=2.16 x σ or σ(max)=720/t; Also σ(max)=80.
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A flat plate 30mm wide and “t”mm wide is subjected to a te...
5mm thick is subjected to a tensile load of 10 kN. Determine the normal stress on the plate.
Solution:
The normal stress is given by the formula:
σ = F/A
where σ is the normal stress, F is the tensile load and A is the cross-sectional area of the plate.
The cross-sectional area of the plate is:
A = width x thickness
A = 30mm x 5mm
A = 150 mm²
Substituting the values in the formula, we get:
σ = 10 kN / 150 mm²
σ = 66.67 MPa
Therefore, the normal stress on the plate is 66.67 MPa.
Solution:
The normal stress is given by the formula:
σ = F/A
where σ is the normal stress, F is the tensile load and A is the cross-sectional area of the plate.
The cross-sectional area of the plate is:
A = width x thickness
A = 30mm x 5mm
A = 150 mm²
Substituting the values in the formula, we get:
σ = 10 kN / 150 mm²
σ = 66.67 MPa
Therefore, the normal stress on the plate is 66.67 MPa.
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A flat plate 30mm wide and “t”mm wide is subjected to a tensile force of 5kN. The plate has a circular hole of diameter 15mm with the centre coinciding with the diagonal intersection point of the rectangle. If stress concentration factor=2.16, find the thickness of the plate if maximum allowable tensile stress is 80N/mm².a)8mmb)9mmc)10mmd)12mmCorrect answer is option 'B'. Can you explain this answer?
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